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2 years ago

What is force? In physics class eleven

Physics

1 answer:

spayn [35]2 years ago

4 0

Answer:

Explanation:

In Physics, force is defined as: The push or pull on an object with mass that causes it to change its velocity. Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a directionForce is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction. The direction towards which the force is applied is known as the direction of the force and the application of force is the point where force is applied.

The Force can be measured using a spring balance. The SI unit of force is Newton(N).

You might be interested in

The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the

PIT_PIT [208]

The drag force is directly proportional to the square of the velocity of motion of the object. So as the speed is doubled, the magnitude of drag force will get quadrupled.

<u>Explanation: </u>

Drag force is the opposing or resisting force acting on any object by the medium in which it is moving. So in this case, you are riding a bicycle, thus the medium can be considered as air.

The formula for calculating drag force is as below:

$\text {Drag force }=\frac{1}{2} \rho v^{2} C_{D} A$

Here, ρ is the density of the air molecules, v is the velocity or speed of the bicycle, CD is the drag coefficient and A is the area of the bicycle.

In the above equation, only the term velocity will be a varying quantity with respect to time and other quantities will remain constant throughout the single situation of riding of bicycle.

So, the equation can be,

$\text { Drag force }=k v^{2}$

Where ,

$k=\frac{1}{2} \rho C_{D} A$ (constant for this whole condition)

Now given the speed of bicycle increased from v to 2v, so the initial drag force will be

$N_{i}=k v^{2}$

After increase in speed, the final drag force will be

$N_{f}=k(2 v)^{2}$

$N_{f}=4 k v^{2}=4 N_{i}$

Thus, if the speed of the bicycle is doubled, the drag force will get increased by four times.

4 0

3 years ago

A train has a final velocity of 110 km/h. It accelerated for 36 s at 0.50 m/s2 . What was its initial velocity

Tems11 [23]

The initial velocity of the train is 12.56 m/s.

<h3>Initial velocity</h3>

The initial velocity of the train can be determined by using the first kinematic equation as shown below;

v = u + at

u = v - at

where;

v is the final velocity = 110 km/h = 30.56 m/s
u is the initial velocity

u = 30.56 - (36 x 0.5)

u = 12.56 m/s

Thus, the initial velocity of the train is 12.56 m/s.

Learn more about initial velocity here: brainly.com/question/19365526

3 0

2 years ago

She falls out of a plane 2 miles up, equipped with a parachute as well as a backup parachute, they both fail. How much time does

Minchanka [31]

D=Vot+1/2at^2

Vot= 0 since there is no initial velocity in the y direction.

a=gravitational acceleration which is - 32 ft/s^2 in imperial units I believe.

She travels a distance of -2 miles, so

-2 miles= 1/2(-32ft/s^2)t^2

t= square root((- 4 miles)/(-32ft/s^2))

I don't know imperial units, but convert miles to feet then solve for t.

8 0

3 years ago

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass 2kg. When a certain con

BARSIC [14]

Answer:

The acceleration of the second object is 4 m/s².

Explanation:

Given that,

when the a constant force acts upon an object, the acceleration varies inversely with its mass .

$mass\propto \frac{1}{acceleration}$

We can rewrite the equation as

$\frac{m_1}{m_2}=\frac{a_2}{a_1}$

When an a certain constant force acts upon an object with mass 2 kg , the acceleration of the object is 26 m/s².

Here, $m_1$ = 2 kg, $a_1$ = 26 m/s², $m_2$ = 13 kg and $a_2=?$

$\frac{m_1}{m_2}=\frac{a_2}{a_1}$

$\frac{2}{13}=\frac{a_2}{26}$

$\Rightarrow \frac{a_2}{26}= \frac{2}{13}$

$\Rightarrow {a_2}= \frac{2}{13}\times 26$

$\Rightarrow a_2=4$ m/s²

The acceleration of the second object is 4 m/s².

3 0

3 years ago

Solve the problems. Show all work, be SI units for force for weight) .

Sav [38]

Answer:

1. 75 N

2. 6.8351 N

3. 700 N

Explanation:

1. Determination of the weight of the bowling ball:

Mass (m) = 7.5 kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 7.5 × 10

W = 75 N

2. Determination of the weight of the object.

Mass (m) = 683.51 g

Weight (W) =?

We'll begin by converting 683.51 g to kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

683.51 g = 683.51 g × 1 Kg / 1000 g

683.51 g = 0.68351 Kg

Thus, 683.51 g is equivalent to 0.68351 Kg.

Finally, we shall determine the weight of the object as follow:

Mass (m) = 0.68351 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 0.68351 × 10

W = 6.8351 N

3. Determination of the weight of the KHS student.

Mass (m) = 154 lb

Weight (W) =?

We'll begin by converting 154 lb to Kg. This can be obtained as follow:

2.2 lb = 1 Kg

Therefore,

154 lb = 154 lb × 1 Kg / 2.2 lb

154 lb = 70 kg

Thus, 154 lb is equivalent to 70 kg.

Finally, we shall determine the weight of the KHS student as follow:

Mass (m) = 70 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

Weight = mass × acceleration due to gravity

W = m × g

W = 70 × 10

W = 700 N

8 0

2 years ago

What is force? In physics class eleven​

What is force? In physics class eleven