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lys-0071 [83]
1 year ago
6

What is one advantage of using primary sources when doing research on an

Physics
1 answer:
WITCHER [35]1 year ago
5 0

One advantage of using primary sources when doing research on an experiment is, it contain more details about the experiment. Thus, option D is right .

To find the answer, we have to know more about the Primary sources.

<h3>What is the advantages of primary sources?</h3>
  • Primary sources are the direct or first-hand excerpts that scientists have independently written based on their experiments in order to support their research.
  • Utilizing original sources encourages analytical and critical thought in relation to the research.
  • It aids in exploring from various angles, which leads to the discovery of extra facts.
  • Primary data aids in navigating the conflicts. Since it is a direct resource related to the experiment, it serves as evidence for the data.

Thus, we can conclude that, Primary sources contain more details about the experiment.

Learn more about the Primary sources here:

brainly.com/question/24190082

#SPJ9

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4. Calculate the total resistance for two 180 ohm resistors connected in<br> parallel
solmaris [256]

Answer:

90 ohms

Explanation:

1/r = 1/180 + 1/180

1/r= 2/180

take the reciprocal of 2/180 which is 180/2 and its 90 ohms

3 0
3 years ago
A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio
DanielleElmas [232]

Answer:

\alpha =-2.2669642\times^{-10}rad/s^2

Explanation:

Angular acceleration is defined by \alpha =\frac{\Delta \omega}{\Delta t}=\frac{\omega_f-\omega_i}{\Delta t}

Angular velocity is related to the period by \omega=\frac{2\pi}{T}

Putting all together:

\alpha =\frac{\frac{2\pi}{T_f}-\frac{2\pi}{T_i}}{\Delta t}=\frac{2\pi}{\Delta t}(\frac{1}{T_f}-\frac{1}{T_i})

Taking our initial (i) point now and our final (f) point one year later, we would have:

\Delta t=1\ year=(365)(24)(60)(60)s=31536000&#10;s

T_i=0.0786s

T_f=0.0786s+7.03\times10^{-6}s

So for our values we have:

\alpha =\frac{2\pi}{\Delta t}(\frac{1}{T_f}-\frac{1}{T_i})=\frac{2\pi}{31536000s}(\frac{1}{0.0786s+7.03\times10^{-6}s}-\frac{1}{0.0786s})=-2.2669642\times^{-10}rad/s^2

Where the minus sign indicates it is decelerating.

8 0
3 years ago
Sort these statements about machines based on whether they are correct or incorrect.
insens350 [35]

as well.

1. Correct

Explanation

An inclined plane is a flat  surface which lie at an angle, Its one end is higher than the other this inclined plane is used as an aid for raising or lowering a load. Staircase also work in similar manner

2. Correct

Explanation

yes all simple machine have a fulcrum

3. Incorrect

Explanation

when we swim that time our arms and legs 'push' the water due to which water displaced in backward direction so her we applied a positive work on the water. According to Newton's Third Law,same magnitude of work is done by water in opposite direction to push us back on our arms and legs. therefore water also does positive work on us.

4. incorrect

Explanation

The force exerted by a machine on an object is input force

5.  Incorrect

Explanation

when the input force is greater than the output force that time machine have mechanical advantage of less than 1.


8 0
2 years ago
Read 2 more answers
5.
lesantik [10]

Answer:

It is B

it is called a jumper cable because it jumps the power from one car to the other

3 0
3 years ago
An avant-garde composer wants to use the Doppler effect in his new opera. As the soprano sings, he wants a large bat to fly towa
Allisa [31]

Answer:

     v’= 9.74 m / s

Explanation:

The Doppler effect is due to the relative movement of the sound source and the receiver of the sound, in this case we must perform the exercise in two steps, the first to find the frequency that the bat hears and then the frequency that the audience hears that also It is sitting.

Frequency shift heard by the murciela, in case the source is still and the observer (bat) moves closer

        f₁ ’= f₀ (v + v₀)/v

         

Frequency shift emitted by the speaker in the bat, in this case the source is moving away from the observer (public sitting) that is at rest

         f₂’= f₁’ v/(v - vs)

           

Note that in this case the bat is observant in one case and emitter in the other, called its velocity v’

            v’= vo = vs

Let's replace

           f₂’= f₀   (v + v’)/v   v/(v -v ’)

           f₂’= f₀   (v + v’) / (v -v ’)

           (v –v’ ) f₂’ / f₀ = v + v ’

           v’ (1+ f₂’ /f₀) = v (f₂’/fo - 1)

           v’ (1 + 1.059) = 340 (1.059 - 1)

           v’= 20.06 / 2.059

           v’= 9.74 m / s

6 0
3 years ago
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