Answer:
I belive it would be ture
Explanation:
It's been a while since I learned this but I think that is right.
Answer:

Explanation:
We are given that
Gravitational force=
r=0,U(0)=0
We know that
Gravitational potential energy=


Substitute r=0 ,U(0)=0


Substitute the value

Necrosis - the death of most or all of the cells in an organ or tissue due to disease, injury, or failure of the blood supply.
Hope this helps, please mark me brainliest
<span>Social
i think so ,but i am not sure</span>
Answer:

Explanation:
Torque is defined as the cross product between the position vector ( the lever arm vector connecting the origin to the point of force application) and the force vector.

Due to the definition of cross product, the magnitude of the torque is given by:

Where
is the angle between the force and lever arm vectors. So, the length of the lever arm (r) is minimun when
is equal to one, solving for r:
