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3 years ago

All the bats living in a cave form a _______ of bats in the cave ecosystem.

Physics

1 answer:

kramer3 years ago

8 0

I am sorry I cant find the answer. I was hoping to find the answer

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Force and distance are used to calculate work. Work is measured in which unit? joules watts newtons meters

elena55 [62]

Answer:

The unit of work is joules

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3 years ago

What is the best description of temperature?

Nonamiya [84]

Explanation:

o has Celsius of indirect measurment

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3 years ago

Which of the following statements about sunspots is false? a. They are areas of the sun that are "burnt out." c. They are cooler

PSYCHO15rus [73]

Answer: Option (a) is the correct answer.

Explanation:

Sunspots are defined as the dark and cooler areas on the surface of the Earth. A sunspot is present in a region known as photosphere.

Temperature of a sunspot is about 3,800 degrees Kelvin whereas photosphere has a temperature of about 5,800 degree kelvin.

Thus, we can conclude that out of the given options, the statement they are areas of the sun that are "burnt out" is false about sunspots.

8 0

3 years ago

Read 2 more answers

g power output of 87 W. At what distance will the decibel reading be 120 dB, which is noise level of a loud indoor rock concert

Kazeer [188]

Given that,

Output power = 87 W

Decibel reading = 120 dB

We need to calculate the intensity of sound

Using formula of intensity of sound

$dB=10\log(\dfrac{I}{I_{0}})$

Put the value into the formula

$120=10\log(\dfrac{I}{1\times10^{-12}})$

$12=log(\dfrac{I}{1\times10^{-12}})$

$10^{12}=\dfrac{I}{1\times10^{-12}}$

$I=10^{12}\times1\times10^{-12}$

$I=1\ W/m^2$

We need to calculate the distance

Using relation of power out[ut and intensity

$I=\dfrac{P}{4\pi r^2}$

Put the value into the formula

$1=\dfrac{87}{4\pi r^2}$

$r=\sqrt{\dfrac{87}{4\pi}}$

$r=2.63\ m$

Hence, The distance is 2.63 m

7 0

3 years ago

Usually wire resistance can be neglected. But we see the effect of it sometimes when a light dims as another high-current device

tangare [24]

Please find the figure attached below:

Answer:

a.Resistance of bulb= $R_{2}$ =192 ohm

b.power consumed by bulb after motor disconnection=74.609 W

Explanation:

a.Resistance of bulb= $R_{2}$ =?

As we know that $P=\frac{P^{2} }{R}$

putting R as resistance of bulb i.e. $R=R_{2}$

$P=\frac{V^{2}}{R_{2} }\\R_{2}=\frac{V^{2}}{P} \\ R_{2}=\frac{(120)^{2} }{75}\\ R_{2}=192ohm$

b.power consumed by bulb after motor disconnection?

from the figure we see that $R_{1}\ and\ R_{2}$ are in series so

$R_{eq}=R_{1} +R_{2} \\R_{eq}=192+0.5\\R_{eq}=192.5ohm$

current through their resistance is

$I_{eq}=\frac{V}{R_{eq} }\\ I_{eq}=\frac{120}{192.5 } \\I_{eq}=0.6233A$

Power consumed by bulb is

$P_{b} =I^{2}R\\\\ P_{b} =(0.6233)^{2}(192)\\\\P_{b} =74.609W$

3 0

3 years ago