If the surface is perfectly frictionless AND level ... no ups and downs ... then the puck never slows down or stops. There's nothing to make it do so. (Notice that "perfectly frictionless" means no air resistance either.)
This is difficult to explain, but it's hypotonic. HypERtonic is where there is where the cells shrivel up because there is more solute (salt is an example of a solute) on the outside, so the water rushes outward towards it and shrivels the cell. Plants like lots of water so they like to be hypotonic, and since you're adding pure H2O, there is no solute being added, so the solute is in the cell, causing the water to rush in. Isotonic is equal throughout the solution.
<u>Answer:</u>
If 100 and 110 photons hit an atom and 63 electrons are emitted due to the threshold frequency
<u>Explanation:</u>
Because of the effect of threshold frequency. Both the times 63 electrons are only emitted and its due to the level of threshold value.
Threshold frequency is can be defined as the minimum frequency at which electrons will be getting emitted when it hits. If none of the electrons are getting ejected, this states that the frequency of the light is lesser than the threshold frequency
Answer:
The magnitude of the acceleration of a proton at a distance of 1.5cm from the bead is 5.6 x10^13m/s².
The magnitude of the acceleration of a proton at a distance of 1.5cm from the bead is 9.8 x10^16m/s².
Explanation:
Newton's second law states that the total sum of the force acting on a particle in motion is equal to the mass of the particle times the acceleration due to the force. So the electric force between the bead and proton is equal to ma. That is,
Fe = kq1*q2/r² = m*a
The proton had a charge of +1.6x10^-19C and a mass of 1.67×10^-27kg
By substituting these values into the equivalent for a we have that the acceleration of the proton at a distance of 1.5cm form the bead is 5.6×10^13m/s²
The proton had a charge of -1.6x10^-19C and a mass of 9.10×10^-31kg
By substituting these values into the equivalent for a we have that the acceleration of the proton at a distance of 1.5cm form the bead is 9.8×10^16m/s²
That’s True (N-S) attract and (N-N or S-S) repel