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MakcuM [25]
3 years ago
10

A 75 kg refrigerator is located on the 70th floor of skyscraper (300 meters above ground). What is the potential energy of the r

efrigerator. (PE=MGH(G=9.8M/S²)​
Physics
2 answers:
Anna71 [15]3 years ago
6 0

Answer:

220,500 Joules

Explanation:

PE = (75 kg) x (9.8 m/s^{2}) x (300 m)

PE = (735) x (300)

PE = 220,500 Joules

garri49 [273]3 years ago
3 0

Answer:

googli moogli

Explanation:

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