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3 years ago

What does the electric field strength tell about the electric firld?

Physics

1 answer:

Solnce55 [7]3 years ago

8 0

Answer:

Explanation:

The region around a charged particle where another charged particle experiences a force of attraction or repulsion is called electric field.

The strength of electric field is defined as the force experienced by the unit positive test charge.

E = F / q

Electric field strength is a vector quantity and it is measured in newton per coulomb.

Where, F is the force of attraction or repulsion between the two charges and q is the test charge on which the electric field strength is to be calculated.

The strength of electric field is more if the field is strong. It means more be the electric field strength at a point more be the electric field.

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3 years ago

The resistance of a wire depends upon the material's resistivity and the length and cross‑sectional area of the wire. What will

andriy [413]

Answer:

R' = 4R

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Explanation:

The resistance of a wire at room temperature, is given by the following formula:

R = ρL/A ----------- equation 1

where,

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ρ = resistivity of the material

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A = Cross-sectional area of wire

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using equation 1:

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3 years ago

While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th

Dovator [93]

Answer:

Explanation:

From the given information:

radius = 15 m

Time T = 23 s

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$v = \dfrac{2\times \pi \times 15}{23}$

v = 4.10 m/s

b) The magnitude of the acceleration is:

$a = \dfrac{v^2}{r} \\ \\ a = \dfrac{(4.10)^2}{15}$

a = 1.12 m/s²

c) True weight = mg

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From the top;

the normal force = upward direction,

weight is downward as well as the acceleration.

true weight - normal force = ma

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From the bottom;

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apparent weight - true weight = ma

apparent weight = true weight + ma

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$\dfrac{apparent \ weight }{true \ weight} =1+ \dfrac{a}{g} \\ \\ = 1 + \dfrac{1.12}{9.8}$

$= 1 + \dfrac{1.12}{9.8} \\ \\$

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3 years ago

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beks73 [17]

Answer:

Explanation:

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3 years ago