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sertanlavr [38]
3 years ago
14

A 100. ml portion of 0.250 m calcium nitrate solution is mixed with 400. ml of 0.100 m nitric acid solution. what is the final c

oncentration of the nitrate ion?
Chemistry
1 answer:
pshichka [43]3 years ago
6 0
<span>Answer: Moles Ca(NO3)2 = 100 x 0.250 / 1000 = 0.025 Ca(NO3)2 >> Ca2+ + 2NO3- Moles NO3- = 2 x 0.025 = 0.05 Moles HNO3 = 400 x 0.100 / 1000 = 0.04 Total moles = 0.05 + 0.04 = 0.09 Total volume = 500 ml = 0.500 L M = 0.09 / 0.500 = 0.18</span>
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a 25 ml volume of a sodium hydroxide solution requires 19.6 mL of a 0.189 M HCl acid for neutralization. A 10 mL volume of phosp
Drupady [299]

Answer: 0.172 M

Explanation:

a) To calculate theconcentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=0.189M\\V_1=19.6mL\\n_2=1\\M_2=?\\V_2=25mL

Putting values in above equation, we get:

1\times 0.189\times 19.6=1\times M_2\times 25\\\\M_2=0.148

b) To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_3PO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?\\V_1=10mL\\n_2=1\\M_2=0.148\\V_2=34.9mL

Putting values in above equation, we get:

3\times M_1\times 10=1\times 0.148\times 34.9\\\\M_1=0.172M

The concentration of the phosphoric acid solution is 1.172 M

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Write a balanced equation for the reaction of sulfuric acid (H,SO) and
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Answer:

Explanation:

Word equation:

sulfuric acid + ammonium hydroxide  →  ammonium sulfate + water

Chemical equation:

H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O

Balanced chemical equation:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O

The given reaction is the reaction of acid with base. When acid and base react salt and water are produced. In given reaction an acid sulfuric acid and base ammonium hydroxide react and form ammonium sulfate salt and water. The given reaction also follow the law of conservation of mass.

Steps to balance the equation:

Steps 1;

H₂SO₄ + NH₄OH → (NH₄)₂SO₄ + H₂O

H = 7                            H = 10

S = 1                             S = 1

O = 5                           O = 5

N = 1                            N = 2

Step 2:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + H₂O

H = 12                            H = 10

S = 1                             S = 1

O = 6                           O = 5

N = 2                           N = 2

Step 3:

H₂SO₄ + 2NH₄OH → (NH₄)₂SO₄ + 2H₂O

H = 12                            H = 12

S = 1                               S = 1

O = 6                             O = 6

N = 2                             N = 2

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3 years ago
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