Question

the mass concentration the mass concentration for a solution containing 45 g of calcium carbonate is 100 cm3 ​

Answer 1

Answer: The mass concentration for a solution containing 45 g of calcium carbonate for 100 $cm^{3}$ is 0.045 M.

Explanation:

Given: Mass of calcium carbonate = 45 g

Volume = $100 cm^{3}$

Convert $cm^{3}$ into L as follows.

$1 cm^{3} = 0.001 L\\100 cm^{3} = 100 cm^{3} \times \frac{0.001 L}{1 cm^{3}}\\= 0.1 L$

Moles of calcium carbonate (molar mass = 100 g/mol) is as follows.

$No. of moles = \frac{45 g}{100 g/mol}\\= 0.45 mol$

Molarity is the number of moles of solute present in a liter of solution.

Hence, molarity (or mass concentration) of given solution is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.45 mol}{0.1 L}\\= 0.045 M$

Thus, we can conclude that the mass concentration for a solution containing 45 g of calcium carbonate for 100 $cm^{3}$ is 0.045 M.