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mezya [45]
3 years ago
15

Calculate the atomic mass (average atomic mass) of naturally occurring oxygen.

Chemistry
1 answer:
sveticcg [70]3 years ago
5 0
<span>Atomic mass is, literally, a measure of mass. 

</span><span>One atomic mass unit is a very, very, very, very, very, very small fraction of a gram.

It is actually defined using the most common isotope of carbon, which is carbon-12.  

The average atomic mass of Oxygen is 15.999 u. </span>
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Write 0.00000009345 in Engineering Notation with 3 significant figures
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Answer:

93.43\times 10^{-9}

Explanation:

Scientific notation is the way of writing numbers which are either large or small. The number is written in the scientific notation when the number is between 1 and 10 and then multiplied by the power of 10. Engineering notation is the same version of the scientific notation but the number can be between 1 and 1000 and in this exponent of the ten is divisible by three.

For example, 1000^2 is to be written as 10^6 in engineering notation.

The given number:

0.00000009345 can be written as 93.425\times 10^{-9}

Answer upto 4 significant digits = 93.43\times 10^{-9}

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Read 2 more answers
If kc = 7.04 × 10-2 for the reaction: 2 hbr(g) ⇌h2(g) + br2(g), what is the value of kc for the reaction: 1/2 h2(g) + 1/2 br2 ⇌h
Kay [80]
At the first reaction when 2HBr(g) ⇄ H2(g) + Br2(g)
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7.04X10^-2 = [H2][Br] / [HBr]^2

at the second reaction when 1/2 H2(g) + 1/2 Br2 (g) ⇄ HBr
Its Kc value will = [HBr] / [H2]^1/2*[Br2]^1/2
we will make the first formula of Kc upside down:
1/7.04X10^-2 = [HBr]^2/[H2][Br2]
and by taking the square root: 
∴ √(1/7.04X10^-2)= [HBr] / [H2]^1/2*[Br]^1/2
∴ Kc for the second reaction = √(1/7.04X10^-2) = 3.769 
7 0
3 years ago
Why bromine is a ring deactivator as it is ortho-Para directing group??
Anettt [7]

Answer:

here you go

Explanation:

Halogens are very electronegative. This means that inductively they are electron withdrawing. However, because of their ability to donate a lone pair of electrons in resonance forms, they are activators and ortho/para directing. Electron withdrawing groups are meta directors and they are deactivators.

7 0
3 years ago
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