mass = 12.2 kg
Explanation:
To find the mass we use the following formula (Newton's Second Law of Motion):
force = mass × acceleration
mass = force / acceleration
mass = 2.32 N / 0.19 m/s²
mass = 12.2 kg
Learn more about:
Newton's Second Law of Motion
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Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds.
Ex: cutting a paper, gaining weight, cutting hair
The new volume of the air bubble that has an initial volume of 5.0 ml released at the bottom of a lake where the pressure is 3.0 atm is 15mL.
<h3>How to calculate volume?</h3>
The volume of a given gas can be calculated by using the following formula:
P1V1 = P2V2
Where;
- P1 = initial pressure
- V1 = initial volume
- P2 = final pressure
- V2 = final volume
5 × 3 = 1 × V2
15 = V2
V2 = 15mL
Therefore, the new volume of the air bubble that has an initial volume of 5.0 ml released at the bottom of a lake where the pressure is 3.0 atm is 15mL.
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Answer : The excess reactant in the combustion of methane in opem atmosphere is 
molecule.
Solution : Given,
Mass of methane = 23 g
Molar mass of methane = 16.04 g/mole
The Net balanced chemical reaction for combustion of methane is,
First we have to calculate the moles of methane.
= 
= 1.434 moles
From the above chemical reaction, we conclude that
1 mole of methane react with the 2 moles of oxygen
and 1.434 moles of methane react to give 
moles of oxygen
The Moles of oxygen = 2.868 moles
Now we conclude that the moles of oxygen are more than the moles of methane.
Therefore, the excess reactant in the combustion of methane in open atmosphere is molecule.
like stuff getting stuck to the fishermen hooks , net etc
