Which element's atomic radius increases the most in size when it becomes ionized? A. Sodium B. Chlorine C. Fluorine D. Lithium

The element iridium exists in nature as two isotopes: 191Ir has a mass of 190.9606 u, and 193Ir has a mass of 192.9629 u. The av

nlexa [21]

Answer: The percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope be 'x'. So, fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope will be '1 - x'

For $_{77}^{191}\textrm{Ir}$ isotope:

Mass of $_{77}^{191}\textrm{Ir}$ isotope = 190.9606 amu

Fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope = x

For $_{77}^{193}\textrm{Ir}$ isotope:

Mass of $_{77}^{193}\textrm{Ir}$ isotope = 192.9629 amu

Fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope = 1 - x

Average atomic mass of iridium = 192.22 amu

Putting values in equation 1, we get:

$192.22=[(190.9606\times x)+(192.9629\times (1-x))]\\\\x=0.3710$

Percentage abundance of $_{77}^{191}\textrm{Ir}$ isotope = $0.3710\times 100=37.10\%$

Percentage abundance of $_{77}^{193}\textrm{Ir}$ isotope = $(1-0.3710)=0.6290\times 100=62.90\%$

Hence, the percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

8 0

3 years ago

Iodine-131 is a radioactive isotope that is used in the treatment of cancer of the thyroid. The natural tendency of the thyroid

Finger [1]

Answer:

a) Binding Energy = 1084.266 MeV

b) Binding energy per nucleon = 8.28 MeV

Explanation:

Binding Energy, $BE = \triangle M * 931.5$

Where ΔM = Mass defect of Iodine-131

The mass of iodine-131 = 130.906124 u.

Number of protons in Iodine-131 = 53

Number of neutrons in Iodine-131 = 78

Mass of a proton = 1.007276 u

Mass of neutron = 1.008664 u

Total mass of the 53 protons in Iodine-131 = (53*1.007276)

Total mass of the 53 protons in Iodine-131 = 53.39 u

Total mass of the 78 protons in Iodine-131 = (78*1.008664)

Total mass of the 78 protons in Iodine-131 = 78.68 u

$\triangle M = (53.39 + 78.68) - 130.906124\\\triangle M = 1.164 u$

Binding Energy = 1.164 * 931.5

Binding Energy = 1084.266 MeV

b) Binding Energy per nucleon

The mass of the nucleon of iodine 131 = 130.906124

Binding Energy per nucleon = 1084.266/130.906124

Binding energy per nucleon = 8.28 MeV

5 0

4 years ago

¿ cómo distinguirían el agua con el aceite?

Nastasia [14]

Answer:

Se pueden separar dos líquidos inmiscibles, aceite y agua, mediante el uso de un embudo de separación. La mezcla de aceite y agua forma dos capas separadas porque son completamente insolubles entre sí. El aceite forma la capa superior mientras que el agua forma la inferior.

Explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

7 0

3 years ago

what is the net electrical charge on a magnesium ion that is formed when a neutral atom loses two electrons?

nasty-shy [4]

This magnesium ion will have a charge of +2. This is because it retained the same number of protons and neutrons, but the loss of 2 electrons (with negative charge) means that there are now 2 extra protons compared to electrons, and those 2 protons give a net charge of +2.

4 0

3 years ago

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Ionic compounds can conduct electricity when dissolved in water or melted, because

emmainna [20.7K]

I believe the correct response would be A. The ions once dissolved in the solution are free to move

5 0

4 years ago

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