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Marat540 [252]
3 years ago
15

If you graph both sides of the equation 2(2x + 3) = 4x + 6, what will the graph look like?

Mathematics
2 answers:
Tasya [4]3 years ago
4 0

Answer:

The graphs are identical and intersect at infinitely many points.  

Step-by-step explanation:

Given the equation

2(2x + 3) = 4x + 6

we have to compare the graph of both sides of equation.

LHS: 2.(2x + 3)

By distributive property,

a.(b+c)=a.b+a.c

2.(2x + 3)=2.2x+2.3=4x+6

\text{The above expression implies 4x+6}

which is equals to RHS of given equation i.e

4x+6=4x+6

The both sides of equation are identical.

Since both sides of equation are identical therefore intersect at infinitely many points.

Option 3 is correct.

Arturiano [62]3 years ago
3 0
Distribute on the left
4x+6=4x+6

Because the equations are exactly the same, they are coinciding and all point intersect. Therefore, there are infinitely many solutions.

Final answer: C
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An elephant needs to drink at least 40 gallons of water each day. A drinking tank contains 4 gallons of water. The elephant has
kirill115 [55]

Answer:

x≥4

Step-by-step explanation

24+4x≥40. Subtract 24 from both sides to get 4x≥16. Divide both sides by 4 to get x≥4.

6 0
3 years ago
Read 2 more answers
The weights of 83 randomly selected windshields were found to have a variance of 1.88. Construct the 95% confidence interval for
Morgarella [4.7K]

Answer:

95% confidence interval for the population variance = (1.42 , 2.62).

Step-by-step explanation:

We are given that the weights of 83 randomly selected windshields were found to have a variance of 1.88.

<em>So, firstly the pivotal quantity for 95% confidence interval for the population variance is given by;</em>

        P.Q. = \frac{(n-1)s^{2} }{\sigma^{2} } ~ \chi^{2} __n_-_1

where, s^{2} = sample variance = 1.88

           \sigma^{2} = population variance

            n = sample of windshields = 83

So, 95% confidence interval for population variance, \sigma^{2} is;

P(58.85 < \chi^{2} __8_2 < 108.9) = 0.95 {As the table of \chi^{2} at 82 degree of freedom

                                              gives critical values of 58.85 & 108.9}

P(58.85 < \frac{(n-1)s^{2} }{\sigma^{2} } < 108.9) = 0.95

P( \frac{ 58.85}{(n-1)s^{2} } < \frac{1 }{\sigma^{2} } < \frac{108.9}{(n-1)s^{2} } ) = 0.95

P( \frac{ (n-1)s^{2}}{108.9 } < \sigma^{2} < \frac{ (n-1)s^{2}}{58.85 } ) = 0.95

<em><u>95% confidence interval for</u></em> \sigma^{2} = ( \frac{ (n-1)s^{2}}{108.9 } , \frac{ (n-1)s^{2}}{58.85 } )

                                                  = ( \frac{ (83-1)\times 1.88}{108.9 } , \frac{ (83-1)\times 1.88}{58.85 } )

                                                  = (1.42 , 2.62)

Therefore, 95% confidence interval for the population variance of the weights of all windshields in this factory is (1.42 , 2.62).

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3 years ago
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Answer:

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Step-by-step explanation:

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Vikki [24]

Answer:

B and D

Step-by-step explanation:

8 0
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Take a look at the figure. What are the coordinates of the point labeled A in the graph shown?
marusya05 [52]
The coordinates of the point labeled A in the graph shown is (2,-2). The 2 is in the x axis while -2 is in the y axis of the graph while point B is in coordinates (-2,-2) and  point C is in coordinates (-2,4).
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