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Slav-nsk [51]
3 years ago
14

Consider the following sets of sample data: A: 136, 99, 118, 134, 120, 130, 131, 135, 115, 118, 118, 136, 133, 110 B: 3.51, 3.66

, 3.05, 4.24, 3.96, 4.73, 3.01, 3.29, 4.55, 4.27, 2.96 Step 1 of 2 : For each of the above sets of sample data, calculate the coefficient of variation, CV. Round to one decimal place.

Physics
1 answer:
Paha777 [63]3 years ago
6 0

Answer:

CV =0.1 , for set A

CV=0.2 , for set B

Explanation:

Check attachment for solution

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Consider a collection of charges in a given region and suppose all other charges are distant and have a negligible effect. Furth
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Answer:

E. Some charges in the region are positive, and some are negative.

Explanation:

Electric potential is given as;

V = \frac{W}{Q}

where;

W is the work done in moving a charge between two points which have a difference in potential

Q is quantity of charge in the given region

If the electric potential at a given point in the region is zero, then sum of the charges in the given region must be equal to zero. For the charges to sum to zero, some will be positive while some will be negative,.

Therefore, the correct statement in the given options is "E"

E. Some charges in the region are positive, and some are negative.

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What is the value of side "a" in the triangle shown below? (1 point)
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Answer: 5

Explanation:

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3 years ago
Two narrow, parallel slits separated by 0.85 mm are illuminated by 600 nm light, and the viewing screen is 2.8 m away from the s
AURORKA [14]

Answer:

Phase difference = pi/4 radians

Explanation:

Given:

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Find:

What is the phase difference between the two interfering waves on a screen, at a point 2.5 mm from the central bright fringe?

Solution:

- The phase difference can be evaluated by determining the type of interference that occurs at point y = 2.5 mm above central order. We will use the derived results from Young's double slit experiment.

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                                  m = d*sin(Q) / λ

- Where, m is the order number and angle Q is the angle for mth order of fringe from central bright fringe.

                                  r = sqrt ( L^2 + 0.0025^ )

Where, r is the distance from split to the interference bright fringe.

                                  r = sqrt(2.8^ + 0.0025^) = 2.8

                                  sin(Q) = 0.0025 / 2.8

Hence.                        m = 0.00085*0.0025 / 2.8*(600*10^-9)

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- We know that constructive interference would occurred at m = 1 and destructive interference @ m = 1.5. They have a phase difference of pi/2 radians.

- The order number lies in between constructive and destructive interference i.e m ≈ 1.25 then the corresponding phase difference = 0.5*(pi/2).

Answer:                  Phase difference = pi/4 radians

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