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Slav-nsk [51]
3 years ago
14

Consider the following sets of sample data: A: 136, 99, 118, 134, 120, 130, 131, 135, 115, 118, 118, 136, 133, 110 B: 3.51, 3.66

, 3.05, 4.24, 3.96, 4.73, 3.01, 3.29, 4.55, 4.27, 2.96 Step 1 of 2 : For each of the above sets of sample data, calculate the coefficient of variation, CV. Round to one decimal place.

Physics
1 answer:
Paha777 [63]3 years ago
6 0

Answer:

CV =0.1 , for set A

CV=0.2 , for set B

Explanation:

Check attachment for solution

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A hollow conducting spherical shell has radii of 0.80 m and 1.20 m, The radial component of the electric field at a point that i
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Complete Question

The complete question is  shown on the first uploaded image  

 

Answer:

The electric field at that point is  E = 7500 \ N/C

Explanation:

From the question we are told that  

       The  radius of the inner circle is r_i  =  0.80  \ m

        The  radius of the outer circle is  r_o  =  1.20 \ m

       The  charge on the spherical shell q_n  =  -500nC  = -500*10^{-9} \ C

      The magnitude of the point charge at the center is  q_c =  + 300 nC  =  + 300 * 10^{-9} \ C

        The  position we are considering is  x =  0.60 m  from the center

Generally  the  electric field  at the distance x =  0.60 m  from the center  is mathematically represented as

                 E =  \frac{k *  q_c   }{x^2}

substituting values  

                  E =  \frac{k *  q_c   }{x^2}

where  k is  the coulomb constant with value k = 9*10^{9}  \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

     substituting values

                  E =  \frac{9*10^9  *  300 *10^{-9}}{0.6^2}

                 E = 7500 \ N/C

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3 years ago
In a fit of rage about distance learning, you throw your computer out the window with an initial velocity of 3 m/s and it breaks
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Answer:

9 m

Explanation:

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a. 0.5 T

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During a full time period T, the mass on the spring oscillates back and forth, returning to its original position. This means that the total distance covered by the mass during a period T is 4 times the amplitude (4A), because the amplitude is just half the distance between the maximum and the minimum position, and during a time period the mass goes from the maximum to the minimum, and then back to the maximum.

So, the time t that the mass takes to move through a distance of 2 A can be found by using the proportion

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and solving for t we find

t=\frac{(1T)(2 A)}{4A}=0.5 T

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Now we want to know the time t that the mass takes to move through a total distance of 5 A. SInce we know that

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we can set the following proportion:

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And by solving for t, we find

t=\frac{(1T)(5 A)}{4A}=\frac{5}{4} T=1.25 T

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According to a college survey, 22% of all students work full time. find the mean for the number of 3) students who work full tim
attashe74 [19]

Assuming that the students worldwide are being considered, because of the extremely large population, this can be considered as a binomial distribution. A normal distribution is used most usually as a fair approximation of the binomial. The mean is the expectation, therefore:<span>
E[x] = np = (16)(0.22) = 3.52 
<span>μ = 3.52 </span></span>

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3 years ago
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