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Arte-miy333 [17]
2 years ago
9

It takes 25N or force to drag a box along the floor at a constant speed. If the coefficient of friction is .3, what is the mass

of the box?
Physics
1 answer:
Nataliya [291]2 years ago
6 0

The mass of the box is 8.5 kg.

<h3>What is mass?</h3>

Mass can be defined as the quantity of matter contained in a body.

To calculate the mass of the box, we use the formula

Formula:

  • F = mgμ............. Equation 1

Where:

  • F = Force
  • m = mass of the box
  • g = acceleration due to gravity
  • μ = coefficient of friction

Make m the subject of the equation

  • m = F/gμ..................... Equation 2

From the question,

Given:

  • F = 25 N
  • g = 9.8 m/s²
  • μ = 0.3

Substitute these values into equation 2

  • m = 25/(0.3×9.8)
  • m = 25/2.94
  • m = 8.5 kg

Hence, the mass of the box is 8.5 kg.

Learn more about mass here: brainly.com/question/26150306

#SPJ1

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At the very end of Wagner's series of operas The Ring of Nibelung, Brunnhilde takes the golden ring form the finger of the dead
Blababa [14]

Answer:

a) 404 m² b) apparent height = 7.5 m

Explanation:

This question is about refraction and total internal refraction.

Here I will take refractive index of air and water

n_{air}=1\\ n_{water}=1.33=4/3

Now let's look at the diagram I have attached here

At some angle A, the light from the ring (yellow point) under water will be totally internally refracted (B = 90°), which means that rays of light (yellow arrow) that make large enough angle A will not be able to escape from the water. Since we assumed that the ring is a point, there will be a critical cone of angle A with the ring at its apex which traces a circle of radius R on the surface of water, which, beyond this radius, no light could escape.

According to snell's law

\frac{sin(B)}{sin(A)} = \frac{n_{water}}{n_{air}} = 4/3

At critical angle B = 90°

\frac{3)}{4}sin(B) = [tex]\frac{3}{4} sin(90^\circ ) = 0.75 = sin(A)

Therefore

A = 48.6^\circ

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h* tan (A) = R\\R =11.3 m

And with that we can find the area

A = \pi R^2=404\ m^2

Additional Problem

For apparent depth from above, we can think that, since we are accustomed to seeing light at the speed of c in air, our brain interpret light from <em>any</em> source to be traveling at c. This causes light that originated under water, which has the speed of

v_{water} = \frac{c}{n_{water}} = 0.75c

to appear as if it has traveled with the same duration as light with speed c

In order for this to happen our brain perceive shortened length  which is the apparent depth.

To put it in mathematical term

t_{travel}=\frac{h_{apparent}}{v_{water}} =\frac{h}{c}

So we get apparent depth

h_{apparent}=0.75h = 7.5\ m

4 0
3 years ago
What is radioactivity?​
alekssr [168]

Answer:

Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. A material containing unstable nuclei is considered radioactive. Three of the most common types of decay are alpha decay, beta decay, and gamma decay, all of which involve emitting one or more particles.

the giving off of rays of energy or particles by the breaking apart of atoms of certain elements (as uranium) 2 : the rays or particles that are given off when atoms break apart.

The three most common types of radiation are alpha particles, beta particles, and gamma rays.

HOPE IT HELPS

BRAINLIEST PLEASR

7 0
3 years ago
Read 2 more answers
Assume a device is designed to obtain a large potential difference by first charging a bank of capacitors connected in parallel
Anon25 [30]

Answer:

8 kV

Explanation:

Here is the complete question

Assume a device is designed to obtain a large potential difference by first charging a bank of capacitors connected in parallel and then activating a switch arrangement that in effect disconnects the capacitors from the charging source and from each other and reconnects them all in a series arrangement. The group of charged capacitors is then discharged in series. What is the maximum potential difference that can be obtained in this manner by using ten 500 μF capacitors and an 800−V charging source?

Solution

Since the capacitors are initially connected in parallel, the same voltage of 800 V is applied to each capacitor. The charge on each capacitor Q = CV where C = capacitance = 500 μF and V = voltage = 800 V

So, Q = CV

= 500 × 10⁻⁶ F × 800 V

= 400000 × 10⁻⁶ C

= 0.4 C

Now, when the capacitors are connected in series and the voltage disconnected, the voltage across is capacitor is gotten from Q = CV

V = Q/C

= 0.4 C/500 × 10⁻⁶ F

= 0.0008 × 10⁶ V

= 800 V

The total voltage obtained across the ten capacitors is thus V' = 10V (the voltages are summed up since the capacitors are in series)

= 10 × 800 V

= 8000 V

= 8 kV

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I'm sure that helps.
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