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Arte-miy333 [17]
2 years ago
9

It takes 25N or force to drag a box along the floor at a constant speed. If the coefficient of friction is .3, what is the mass

of the box?
Physics
1 answer:
Nataliya [291]2 years ago
6 0

The mass of the box is 8.5 kg.

<h3>What is mass?</h3>

Mass can be defined as the quantity of matter contained in a body.

To calculate the mass of the box, we use the formula

Formula:

  • F = mgμ............. Equation 1

Where:

  • F = Force
  • m = mass of the box
  • g = acceleration due to gravity
  • μ = coefficient of friction

Make m the subject of the equation

  • m = F/gμ..................... Equation 2

From the question,

Given:

  • F = 25 N
  • g = 9.8 m/s²
  • μ = 0.3

Substitute these values into equation 2

  • m = 25/(0.3×9.8)
  • m = 25/2.94
  • m = 8.5 kg

Hence, the mass of the box is 8.5 kg.

Learn more about mass here: brainly.com/question/26150306

#SPJ1

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During the annual shuffleboard competition, Renee gives her puck an initial speed of 8.12 m/s. Once leaving her stick, the puck
shutvik [7]
<h2>Answer:2.65 seconds</h2>

Explanation:

Let a be the acceleration.

Let u be the initial velocity.

Let v be the final velocity.

Let t be the time taken.

As we know from the equations of motion,

v=u+at

Given,v=0\\u=8.12ms^{-1}\\a=-3.06ms^{-2}

0=8.12-3.06t

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6 0
3 years ago
A ball thrown horizontally at 12.6 m/s from the roof of a building lands 20.0 m from the base of the building
S_A_V [24]

Answer:

1.59 seconds

12.3 meters

but if you are wise you will read the entire answer.

Explanation:

This is a good question -- if not a bit unusual. You should try and understand the details. It will come in handy.

Time

<u>Given</u>

a = 0 This is the critical point. There is no horizontal acceleration.

d = 20 m

v = 12.6 m/s

<u>Formula</u>

d = vi * t + 1/2at^2

<u>Solution</u>

Since the acceleration is 0, the formula reduces to

d = vi * t

20 = 12.6 * t

t = 20 / 12.6

t = 1.59 seconds.

It takes 1.59 seconds to hit the ground

Height of the building

<u>Givens</u>

t = 1.59 sec

vi = 0     Another critical point. The beginning speed vertically is 0

a = 9.8 m/s^2   The acceleration is vertical.

<u>Formula</u>

d = vi*t + 1/2 a t^2

<u>Solution</u>

d = 1/2 a*t^2

d = 1/2 * 9.8 * 1.59^2

d = 12.3 meters.

The two vi's are not to be confused. The horizontal vi is a number other other 0 (in this case 12.6 m/s horizontally)

The other vi is a vertical speed. It is 0.

7 0
3 years ago
If the number of particles is increased in a balloon what happens to the pressure inside of it?
Klio2033 [76]
The air pressure inside the balloon increases as the number of particles increases.
8 0
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Average speed can be represented by the mathematical expression
nevsk [136]

Average speed is defined as total distance moved in total interval of time

so it is given as

v_{avg} = \frac{distance}{time}

now here is we show distance by "d" and time by"t"

then we will have mathematical expression as follows

v = \frac{d}{t}

5 0
3 years ago
Consider a balloon of mass 0.030kg being inflated with a gas of density 0.54kg/m. What will be the volume of the balloon when it
Nonamiya [84]

the weight of the balloon is .030 * 10 = 0.3 N

the weight of the gas of volume v is 0.54*10 N

The lifting force of a volume of v m³ of displaced air is 1.29v N

so, we need

1.29*10*v = 0.3 + 0.54*10*v

or

1.29v = 0.03+0.54v

7 0
1 year ago
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