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Arte-miy333 [17]
2 years ago
9

It takes 25N or force to drag a box along the floor at a constant speed. If the coefficient of friction is .3, what is the mass

of the box?
Physics
1 answer:
Nataliya [291]2 years ago
6 0

The mass of the box is 8.5 kg.

<h3>What is mass?</h3>

Mass can be defined as the quantity of matter contained in a body.

To calculate the mass of the box, we use the formula

Formula:

  • F = mgμ............. Equation 1

Where:

  • F = Force
  • m = mass of the box
  • g = acceleration due to gravity
  • μ = coefficient of friction

Make m the subject of the equation

  • m = F/gμ..................... Equation 2

From the question,

Given:

  • F = 25 N
  • g = 9.8 m/s²
  • μ = 0.3

Substitute these values into equation 2

  • m = 25/(0.3×9.8)
  • m = 25/2.94
  • m = 8.5 kg

Hence, the mass of the box is 8.5 kg.

Learn more about mass here: brainly.com/question/26150306

#SPJ1

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3 years ago
Which description matches up correctly with each type of particle? Alpha - no mass and no charge; beta - mass of 4 and charge of
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The closest answer is
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3 years ago
A 70 kg human sprinter can accelerate from rest to 10 m/s in 3.0 s. During the same time interval, a 30 kg greyhound can go from
ladessa [460]

Answer:

P_1 = 1166.7 Watt

P_2 = 2000 Watt

Explanation:

Average power for the human sprinter is given as

Power = \frac{\Delta E}{\Delta t}

so we have

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(70)(10^2) - 0}{3}

P_1 = 1166.7 Watt

Average power for greyhound is given as

P = \frac{\frac{1}{2}mv^2 - 0}{\Delta t}

P = \frac{\frac{1}{2}(30)(20^2) - 0}{3}

P_2 = 2000 Watt

3 0
3 years ago
A 100 N force is applied to a 500 kg crate resting on frictionless wheels.
Alla [95]

Answer:

<h2>0.2 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{100}{500}  =  \frac{1}{5}  = 0.2 \\

We have the final answer as

<h3>0.2 m/s²</h3>

Hope this helps you

6 0
2 years ago
Read 2 more answers
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