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2 years ago

Can someone explain to how to calculate this

Physics

1 answer:

Karo-lina-s [1.5K]2 years ago

3 0

answer

option d is the correct answer

explanation

as we know frequency is equal to 1 /t

f= 457 Hz

t=1

SO, 1/457

=0.0022sev

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A rogue band of colonists on the moon declares war and prepares to use a catapult to launch large boulders at the earth. Assume

insens350 [35]

Answer:

2.3 km/s
11 km/s

Explanation:

The system is made up of three body system which are the boulder, earth and the moon also the sum of potential ad kinetic energies are assumed to be the same also note that the boulder was launched from the moon at an initial velocity

A ) Minimum speed of the boulder for it to reach the earth = 2.3 km/s

B) ignoring air resistance the impact speed on earth of a boulder launched at this minimum speed = 11 km/s

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2 years ago

A racetrack has the shape of an inverted cone, as the drawing shows. On this surface the cars race in circles that are parallel

sergey [27]

Answer:

The value of d is 183.51 m.

Explanation:

Given that,

Speed of car = 34.0 m/s

Suppose The car race in the circle parallel to the ground surface is at an angle 40°

The radius of circular path $r = d\cos\theta$

Normal force acting on the car = N

We need to calculate the value of d

Using component of normal force

The horizontal component of normal force is equal to the gravitational force.

$N\cos\theta=mg$ ....(I)

The vertical component of normal force is equal to the centripetal force

$N\sin\theta=\dfrac{mv^2}{r}$ .....(II)

Divided equation (I) by equation (II)

$\tan\theta=\dfrac{v^2}{gr}$

Put the value of g

$\tan\theta=\dfrac{v^2}{g\times d\cos\theta}$

$v^2=\tan\theta\times g\times d\cos\theta$

$v^2=g\times d\sin\theta$

$d=\dfrac{v^2}{g\sin\theta}$

Put the value into the formula

$d=\dfrac{(34.0)^2}{9.8\times\sin40}$

$d=183.51\ m$

Hence, The value of d is 183.51 m.

3 0

3 years ago

An object is placed 10 cm in front of a diverging mirror. What is the focal length of the mirror if the image appears 2 cm behin

Dafna1 [17]

Answer:

the focal length of the mirror is : $f=-2.5\,\,cm$

Explanation:

Use the formula for the formation of image using a divergent mirror and recalling that the image (s') that this mirror formed is virtual, so it is entered as a negative number in the formula. Use the object position (s) as 10, the image position (s') as -2, and derive the value of the focal length:

$\frac{1}{s} +\frac{1}{s'}=\frac{1}{f}\\\frac{1}{10} +\frac{1}{-2}=\frac{1}{f}\\\frac{1}{10} -\frac{1}{2}=\frac{1}{f}\\\frac{10\,f}{10} -\frac{10\,f}{2}=\frac{10\,f}{f}\\f-5\,f=10\\-4\,f=10\\f=-2.5\,\,cm$