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Vika [28.1K]
3 years ago
8

Allicin (C6H10OS2) contains 59.9 g of carbon, 21.7 g of hydrogen, 24.4 g of oxygen, and sulfur. What is the mass percent of sulf

ur in a 162 g sample of the compound?
Chemistry
2 answers:
svp [43]3 years ago
7 0

Plato users: the answer is D. 35.47%

nadya68 [22]3 years ago
4 0
The molar mass of Allicin is 162 which means that you can just divide 64 by 162 since 64 is the mass of sulfur in 1 mole of Allicin (32×2=64).  You should get 0.395 which is 39.5%.

I hope this helps.  Let me know in the comment if anything is unclear.  Also, were you supposed to use the values of carbon, hydrogen, and oxygen given?  I didn't use them because I can't figure out how they can be the right ratios.  162 grams of Allicin should contains 72g of carbon, 10g of hydrogen, 16g of oxygen, and 64g of sulfur.
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Making toast is a physical change.



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4 0
3 years ago
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What happens to the pressure of a gas inside a rigid container if the temperature of a gas decreases?
NikAS [45]

Answer:

If the temperature of gas is decreased the pressure will also goes to decrease.

Explanation:

The pressure and temperature have direct relation. If the temperature of gas will increase the pressure of gas will also goes to increase.

According to the Gay-Lussas's Law,

The pressure of given amount of gas is directly proportional to the absolute  temperature when volume is kept constant.

Mathematical relationship:

P ∝ T

P = kT

P/T = k

and

P₁/T₁ = P₂/T₂

5 0
3 years ago
a toy car is pushed forward with a force of 5N. Air resistance and friction apply a combined force of 3.5N backwards, what is th
AlekseyPX

Answer:

Hi... U should do like this

5 - 3.5=1.5 (N)

6 0
2 years ago
A mixture initially contains A, B, and C in the following concentrations: [A] = 0.650 M, [B] = 1.35 M, and [C] = 0.300 M. The fo
dimaraw [331]

<u>Answer:</u> The value of K_c for given reaction is 0.465

<u>Explanation:</u>

We are given:

Initial concentration of A = 0.650 M

Initial concentration of B = 1.35 M

Initial concentration of C = 0.300 M

Equilibrium concentration of A = 0.550 M

Equilibrium concentration of B = 0.400 M

For the given chemical equation:

                           A+2B\rightarrow C

<u>Initial:</u>                0.65     1.35     0.30

<u>At eqllm:</u>        0.65-x   1.35-2x   0.30+x

Evaluating the value of 'x'

0.650-x=0.550\\\\x=0.100

So, equilibrium concentration of B = 1.35 - 2x = [1.35 - 2(0.100)] = 1.15 M

Equilibrium concentration of C = (0.30 + x) = (0.300 + 0.100) = 0.400 M

The expression of K_c for above equation follows:

K_c=\frac{[C]}{[A][B]^2}

Putting values in above equation, we get:

K_c=\frac{0.400}{0.650\times (1.15)^2}\\\\K_c=0.465

Hence, the value of K_c for given reaction is 0.465

7 0
3 years ago
If the hydroxide ion [OH-] concentration of an aqueous solution is 1 x 10 -3 M, what is the [H+] in the solution? Is the solutio
Dominik [7]

Answer:

pH = 11, The solution is Basic.

Explanation:

We know that;

[OH-] [H+] = 1 × 10^-14

we are given; [OH-] as 1 x 10^ -3 M

Therefore, we can get the [H+] by;

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Thus,

pH = - log (1 ×10^-11 M)

     =  11

pH = 11, which means the solution is basic.

4 0
3 years ago
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