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olchik [2.2K]
3 years ago
9

You have three molecules of glucose (3C6H12O6). How many carbon atoms do you have?

Chemistry
2 answers:
poizon [28]3 years ago
8 0

Answer:

1) The correct answer is option C.

2) the correct answer is option C.

Explanation:

1) Molecular formula of glucose = C_6H_{12}O_6

Number of carbon atoms in single molecule = 6

Number of carbon atoms in 3  molecule of glucose :

\frac{6}{1}\times 3=18 atoms of carbon

There are 18 carbon atoms in the 3 molecules of glucose.

2) Homogeneous mixture is the mixture in which components are evenly distributed throughout the mixture. The shape and size of the particles are identical in the mixture.

Heterogeneous mixture is the mixtures in which component are unevenly distributed throughout the mixture. The shape and size of the particles are not identical in the mixture.

Air is the mixture of gases with 78% of nitrogen gas, 21% of oxygen gas and remaining 1 % are other gases. Air is a homogeneous mixture of different gases.

Where as water, oxygen , alcohol are pure substances.

Rzqust [24]3 years ago
3 0
You have three molecules of glucose (3C6H12O6). How many carbon atoms do you have?C. 18
Your answer is correct

Which of the following is a homogenous mixture of two or more pure substances? 
C. air
Your answer is wrong.
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What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough
olga55 [171]

Answer:

Explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

6 0
2 years ago
C-12 and C-13 are naturally-occurring isotopes of the element carbon. C-12 occurs 98.88% of the time and C-13 occurs 1.108% of t
Veseljchak [2.6K]

Answer:

c) (12×0.9889) + (13×0.01108)

Explanation:

Given data:

Percentage of C-12 = 98.89%

Percentage of C-13 = 1.108%

Atomic mass = ?

Solution:

98.89/100 = 0.9889

1.108/ 100 = 0.01108

Atomic mass = (12×0.9889) + (13×0.01108)

Atomic mass = (11.8668 + 0.144034)

Atomic mass = 12.01084

6 0
4 years ago
Is petroleum potential or kinetic energy
Sav [38]
Petroleum is a potential.
yeah that's my guess.
8 0
3 years ago
Veronica is taking an average of 16 height measurements in a brand-new experiment. Which term is this the best example of? repli
Karolina [17]

Answer:

repetition

Explanation:

Taking an average of 16 height measurements is an example of repetition. Repetition involves making and taking repeated measurements in an experiment.

The goal is to achieve a highly accurate and precise data from the experiment.

  • Replication involves duplicating another experiment and testing to see how valid they are.
  • Since Veronica's experiment is a brand new one, it's hypothesis has not been tested or replicated in any way.
  • Therefore, it is not a replication.
  • But she is repeating the experiment to obtain different values.
3 0
3 years ago
Read 2 more answers
s) Suppose we now collect hydrogen gas, H2(g), over water at 21◦C in a vessel with total pressure of 743 Torr. If the hydrogen g
Elenna [48]

This is an incomplete question, here is a complete question.

Suppose we now collect hydrogen gas, H₂(g), over water at 21°C in a vessel with total pressure of 743 Torr. If the hydrogen gas is produced by the reaction of aluminum with hydrochloric acid:

2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)

what volume of hydrogen gas will be collected if 1.35 g Al(s) reacts with excess HCl(aq)? Express  your answer in liters.

Answer : The volume of hydrogen gas that will be collected is 1.85 L

Explanation :

First we have to calculate the number of moles of aluminium.

Given mass of aluminium = 1.35 g

Molar mass of aluminium = 27 g/mol

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Moles of aluminium}=\frac{1.35g}{27g/mol}=0.05mol

The given chemical reaction is:

2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)

As, hydrochloric acid is present in excess. So, it is considered as an excess reagent.

Thus, aluminium is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

2 moles of aluminium produces 3 moles of hydrogen gas

So, 0.005 moles of aluminium will produce = \frac{3}{2}\times 0.05=0.0750mol of hydrogen gas

Now we have to calculate the mass of helium gas by using ideal gas equation.

PV = nRT

where,

P = Pressure of hydrogen gas = 743 Torr

V = Volume of the helium gas = ?

n = number of moles of hydrogen gas = 0.075 mol

R = Gas constant = 62.364\text{ L Torr }mol^{-1}K^{-1}

T = Temperature of hydrogen gas = 21^oC=[21+273]K=294K

Now put all the given values in above equation, we get:

743Torr\times V=0.075mol\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 294K\\\\V=1.85L

Hence, the volume of hydrogen gas that will be collected is 1.85 L

8 0
4 years ago
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