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Setler [38]
3 years ago
11

The atomicity of bromine is​

Chemistry
1 answer:
aev [14]3 years ago
3 0

Answer:

So, the atomicity of noble gases is 1. Example. ... So, the atomicity of hydrogen, nitrogen, oxygen, chlorine, bromine and iodine is 2 each.

Explanation:

So, the atomicity of noble gases is 1. Example. ... So, the atomicity of hydrogen, nitrogen, oxygen, chlorine, bromine and iodine is 2 each.

could  help

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A 50.6 grams sample of magnesium hydroxide (Mg(OH)2) is reacted with 45.0 grams of hydrochloric acid (HCl). What is the theoreti
zysi [14]
            <span> Mg(OH)2(s) + 2HCl(aq) yield MgCl2(aq) + 2H2O(l)

grams HCl required = (50.6 grams Mg(OH)2) * (1 mol Mg(OH)2 / 58.3197 grams Mg(OH)2) * (2 mol HCl / 1 mol Mg(OH)2) * (36.453 grams HCl / 1 mol HCl) = 63.26 grams HCl required

Since there are only 45.0 grams HCl, then HCl is the limiting reactant.

theoretical yield MgCl2 = (45.0 grams HCl) * (1 mol HCl / 36.453 grams HCl) * (1 mol MgCl2 / 2 mol HCl) * (95.211 grams MgCl2 / 1 mol MgCl2) = 58.6 grams MgCl2 </span>
7 0
3 years ago
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What conclusion can you make about a hypothesis that contradicts an existing theory?
Naddika [18.5K]
What are you making a hypothesis for 
6 0
3 years ago
Given the formulas for the ionic compounds, draw the correct ratio of cations to anions (a) BaSO4, (b) CaF2, (c) Mg3N2, (d) K2O.
Karolina [17]

Answer:

A. It formed by barium(Ba+2) ion and sulfate ( SO42- )

B. It is formed by calcium ion (Ca+2) and two fluoride ions (2F-)

C. It is formed by magnesium ion (Mg+2) and nitride ion (N3-)

D. It is formed by two potassium ions (2 K+) and oxide ion(O2-)

3 0
3 years ago
What is the molar mass of a substance?
OlgaM077 [116]

oops pls forgive me I accidentally did the wrong question.

4 0
3 years ago
Compound X has a molar mass of 416.48 g mol
bazaltina [42]

Answer:

P₂Cl₁₀

Explanation:

From the question given above, the following data were obtained:

Molar mass of compound X = 416.48 g/mol

Percentage of phosphorus (P) = 14.87%

Percentage of Chlorine (Cl) = 85.13%

Molecular formula of X =?

Next, we shall determine the empirical formula of compound X. This can be obtained as follow:

P = 14.87%

Cl = 85.13%

Divide by their molar mass

P = 14.87 / 31 = 0.480

Cl = 85.13 / 35.5 = 2.398

Divide by the smallest

P = 0.480 / 0.480 = 1

Cl = 2.398 / 0.480 = 5

Empirical formula of compound X is PCl₅

Finally, we shall determine the molecular formula of compound X. This can be obtained as follow:

Molar mass of compound X = 416.48 g/mol

Empirical formula = PCl₅

Molecular formula =?

Molecular formula= [Empirical formula]ₙ

[PCl₅]ₙ = 416.48

[31 + (35.5 × 5)]ₙ = 416.48

[31 + 177.5]n = 416.48

208.5n = 416.48

Divide both side by 208.5

n = 416.48 / 208.5

n = 2

Molecular formula = [PCl₅]ₙ

Molecular formula = [PCl₅]₂

Molecular formula = P₂Cl₁₀

Therefore, the molecular formula of compound X is P₂Cl₁₀

4 0
3 years ago
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