1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Setler [38]
3 years ago
11

The atomicity of bromine is​

Chemistry
1 answer:
aev [14]3 years ago
3 0

Answer:

So, the atomicity of noble gases is 1. Example. ... So, the atomicity of hydrogen, nitrogen, oxygen, chlorine, bromine and iodine is 2 each.

Explanation:

So, the atomicity of noble gases is 1. Example. ... So, the atomicity of hydrogen, nitrogen, oxygen, chlorine, bromine and iodine is 2 each.

could  help

You might be interested in
Which atom would it be most difficult to remove an electron from
Norma-Jean [14]
I would be difficult to remove an electron from a Noble or Inert Gas (also known as the group 8 or 0 elements).  This is because they all have filled outermost shells and as such the outermost shell would be held tightly to the nucleus and as such make it difficult to remove.  Examples Helium, Neon, Argon, Xenon, Krypton and Radon 
6 0
3 years ago
I'll give 50 pts and brainliest
e-lub [12.9K]

Answer:

Response is below

Explanation:

The different types of mining are underground, surface, placer, and in-situ. Underground mining uses various materials to excavate resources from beneath the surface of the Earth. Surface mining is a category of mining that in which soil and rock overlying the mineral deposit are removed. Placer mining is the mining of stream bed deposits for minerals. In-situ mining is a mining process used to recover minerals such as copper and uranium through boreholes drilled into a deposit.

3 0
3 years ago
Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B Mass ratio A/B =
LUCKY_DIMON [66]

Answer:

mass ratio of A/B is 2:1

Explanation:

Since the mass of box A = 10g

                mass of box B = 5g

   Mass of box C = mass of box A + mass of box

A ratio compares two quantities. To find the ratio of the two boxes:

  Ratio of A to B = \frac{mass of A}{mass of B}

  Ratio of A to B = \frac{10grams}{5grams} = 2

The mass ratio is 2:1 i.e box A has twice the mass of B

8 0
3 years ago
Argon occupies a volume of 28.3 L at a pressure of 0.36 atm. Find the volume of argon when the pressure is increased to 0.85 atm
FromTheMoon [43]

Answer:

12

Explanation:

Boyles law

P1 (.36)

V1(28.3)

P2(.85)

V2(?)

P1*V1=P2*V2

plug it in, and you get 12

3 0
3 years ago
1 mole of hcl(g) has a greater entropy than 1 mole of hbr(g). true or false
yan [13]
False. Due to:
Entropy increases with molecular size (mass of compound)
HBr has greater molecular size (molar mass) than HCl
The value of standard entropy of HCl(g) is 187 joules/ kelvin 
The value of standard entropy of HBr(g) is 199 joules / kelvin
7 0
4 years ago
Other questions:
  • One of the most important industrial sources of ethanol is the reaction of steam with ethene derived from crude oil: c2h4(g) + h
    15·1 answer
  • What is the reaction that happened between the acidified dichromate paper and the gas sulphur dioxide and what is the name of th
    10·1 answer
  • Worth 80 points!!! I forget energy shells
    7·2 answers
  • HI dissociates to form I2 and H2: 2HI(g) → H2(g) + I2(g) If the concentration of HI changes at a rate of –0.45 M/s, what is the
    7·1 answer
  • Removing the tip of the stem in a young plant will most directly interfere with the production of
    13·1 answer
  • Name the four different types of Spheres belonging to Earth and give examples of Renewable resource and the Biotic factors that
    11·1 answer
  • How do the data support your claim above?
    12·2 answers
  • Please help need 18-20 answer ​
    11·2 answers
  • Help ASAP need help and thank you:)
    6·1 answer
  • What is the molarity of 6 moles (mol) of NaCl dissolved in 2 L of water?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!