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Arada [10]
3 years ago
5

A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?

Physics
2 answers:
poizon [28]3 years ago
6 0

Answer:

\boxed {\boxed {\sf 7.84 \ Joules}}

Explanation:

The formula for potential energy is:

PE=m*g*h

where <em>m </em>is the mass, <em>g</em> is the gravitational acceleration, and <em>h</em> is the height.

The mass of the book is 0.4 kilograms. The gravitational acceleration on Earth is 9.8 m/s². The height of the book is 2 meters.

m=0.4 \ kg \\g=9.8 \ m/s^2 \\h=2\ m

Substitute the values into the formula.

PE=(0.4 \ kg)(9.8 \ m/s^2)(2 \ m)

Multiply the first two numbers.

  • 0.4 kg*9.8 m/s²= 3.92 kg*m/s²
  • If we convert the units now, the problem will be much easier later on.
  • 1 kg*m/s² is equal to 1 Newton. So, our answer of 3.92 kg*m/s² is equal to 3.92 N

PE=(3.92 \ N )(2 \ m)

Multiply.

  • 3.92 N* 2 m=7.84 N*m
  • 1 Newton meter is equal to 1 Joule (this is why we converted the units).
  • Our answer is equal to<u> 7.84 Joules.</u>

PE=7.84  \ J

Aliun [14]3 years ago
4 0

Answer:

7.84 is your answer ok bye

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Explanation:

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It is enclosed by a membrane that is 4,4 nm thick.

We need to find the volume of the cell. The cell is spherical in shape. The volume of a sphere is given by the formula as follows :

V=\dfrac{4}{3}\pi r^3

r is the radius of the sphere, r = 5.5 μm

So,

V=\dfrac{4}{3}\times 3.14\times (5.5)^3\\\\V=696.55\ \mu m^3

So, the volume of the cell is 696.55\ \mu m^3.

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m_a_m_a [10]

Explanation:

When m=<em>mass</em>

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7 0
3 years ago
If an 83.00 g sample of Iron has a starting temperature of 297K and an ending temperature of 329K how much heat will be lost fro
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Question 1 :

m = mass of iron sample = 83

c = specific heat of iron sample = 0.450 J/g ⁰C

T₀ = initial temperature = 297 K

T = final temperature = 329 K

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Heat lost is given as

Q = m c (T - T₀)

inserting the values

Q = (83) (0.450) (329 - 297) = 1195.2 J



Question 2 :

m = mass of sample = 59 g

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c = specific heat

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Q = m c

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Question 3 :


m = mass of sample = 55 g

c = specific heat of sample = ?

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Q = heat absorbed = 3908.3 J

Heat absorbed is given as

Q = m c (T - T₀)

inserting the values

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5 0
3 years ago
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