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babymother [125]

4 years ago

6

How are the mass and weight of an object related? Weight equals mass plus the acceleration due to gravity. Mass equals weight mu

ltiplied by the acceleration due to gravity. Mass and weight are the same. Weight equals mass multiplied by the acceleration due to gravity.

1 answer:

Elanso [62]4 years ago

5 0

Weight equals mass multiplied by the acceleration due to gravity.

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How do natural gas and crude oil compare as energy resources?

Mazyrski [523]

Answer:

Crude oil and natural gas are both energy commodities. As such, we use these fuels to heat and cool our homes or supply other energy needs. The price relationship between crude oil and natural gas is an inter-commodity spread, in which the prices between the two change in relation to each other.

Historically, in an inter-commodity spread, when one becomes more expensive, the other will be more desirable for consumers because of the lower prices and higher supply.

Many companies that produce crude oil also produce natural gas. Natural gas and crude oil exploration and production are often related because the release and capture of natural gas can occur during the oil drilling process.

The relationship between crude oil and natural gas changed around the turn of the 21st century due to the discovery of more natural gas reserves in the United States.

Huge natural gas reserves, previously undiscovered in the Marcellus and Utica shale regions of the U.S., altered the price relationship between these two energy commodities, lowering the price of natural gas in the U.S. while the price of oil continued to rise between 2000 and 2014.

Attributed to slowing growth of emerging economies and a reduction in oil demand, a drastic drop in the price of crude oil occurred in late 2014, continuing through early 2016. By 2018, the price of crude oil crept back up to over $70 per barrel. However, due to the coronavirus in 2020 almost halting demand for oil, crude oil prices dropped to historic lows, while natural gas dropped a little, but held pretty steady.

7 0

3 years ago

Pls help answer 7 and 8

aleksandr82 [10.1K]

Answer:

science is the knowledge gained through observations and experimentations

Characteristics

consistency

observability

predictability

testability

tentativeness

components of nature are soil,atmosphere and radiation

6 0

3 years ago

At a place where an object is thrown vertically downward with a speed of while a different object is thrown vertically upward wi

Bumek [7]

Answer:

Both objects will undergo the same change in velocity

Explanation:

m = Mass of the Earth = 5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6371000 m

m = Mass of object

Any object which is falling has only the acceleration due to gravity.

$ma=\dfrac{GMm}{r^2}\\\Rightarrow a=\dfrac{GM}{r^2}\\\Rightarrow a=\dfrac{6.67\times 10^{-11}\times 5.972\times 10^{24}}{(6.371\times 10^6)^2}\\\Rightarrow a=9.81364\ m/s^2$

The acceleration due to gravity on Earth is 9.81364 m/s²

So, the speeds of the objects will change at an equal rate of 9.81364 m/s² but the change will be negative when an object is thrown up.

Hence, both objects will undergo the same change in velocity.

4 0

4 years ago

The block of weight 113 lb is pushed with a force of P = 31 lb on top of two cylindrical rollers with a weight of 42 lb and a ra

Lilit [14]

Answer:

The block's speed will be of 5,1 ft/s

Explanation:

For this problem solve it is used the work and energy theorem which state:

$W=dK$

Where W is the net work done and dK the change in the kinetic energy between in the time after and before the force is applied. The net work can expressed as:

$W=F.d$

Here F and d are applied force and the displacement. While the kinetc energy for the i body:

$Ki=1/2*m_{1}V_{1}^2+1/2*I_{1}w_{1}^2$

Where mi,Ii Vi, wi are the mass, the moement of inertia, the linear and the angular velocity for the i body respectively. Therefore to calcule the total change in kinetic energy we take into account all the bodies involves, in this case the block and the two rollers. Assuming fixed rollers but can rotate, and the block with linear movement, the final kinect energy is:

$Kf=1/2*m_{b}V_{b}^2+1/2*I_{r1}w_{r1}^2+1/2*I_{r2}w_{r2}^2$

Note since at the beginning the bodies system is at rest hence the initial kinetic energy is null. In the above equation the subscripts b, r1 and r2 relate to the block and the two rollers.

For solid roller the moment of inertia can be calculated as:

$I_{r}=1/2*m_{r}R_{r}$

Where mr and Rr are the mass and radius rollers. Replacing the moment of inertia in the kinetic energy:

$Kf=1/2*m_{b}V_{b}^2+1/4*m_{r1}R_{r1}w_{r1}^2+1/4*m_{r2}R_{r2}w_{r2}^2$

As at the point of contact there is no displacement between the surfaces of the block and the rollers, in that point the linear velocities of this bodies are the same. So can expressed the linear velocity of the block as function of the rotating speed and the rollers radius:

$V_{b}=w_{r}R$

Entering latest in the new kinetic energy expression:

$Kf=1/2*m_{b}.(w_{r}.R)^2+1/4*m_{r}Rw_{r}^2+1/4*m_{r}Rw_{r}^2$

By doing this the kinetic energy expressed only as function of the roller rotating speed. As the roller rotatings speed are the same, and the masses and the radius are known, the the kinetic energy can expressed as:

$Kf=1/2*113\ lb.\1.57\ ft\ w^2+1/4*42\ lb.\ 1.57\ ft\ w^2+1/4*42\ lb.\ 1.57\ ft\ w^2$

$Kf=191\ lb.ft^2 w^2$

Before calculating the work, we will obtain the force in the proper units:

$F=30\ lbf\ *\ 32.16\frac{lb.ft/s}{lbf}$

$F=964.8\ lb.ft/s^2$

Then calculate the work:

$W=964.8\ lb.ft/s\ *\ 2.08\ ft$

$W=2006.8\ lb.ft^2/s^2$

By equating the work and kinetic energy equations and solving for the rotating speed:

$2008.8\ lb.ft^2/s^2=190\ lb.ft^2 w^2$

$w=\sqrt(\frac{2006.8\ lb.ft^2/s^2}{190\ lb.ft^2})$

$w=3.24 1/s$

And finally multiplying the roller rotating speed by the rollers radius, the block speed result:

$V=1.57 ft\ * 3.24 1/s$

$V=5.1 ft/s$

5 0

4 years ago

IRINA_888 [86]

get a cylinder that is about maybe 100cm^3
fill it up with about 30cm^3
place the solid into the cylinder.
take the reading - 30 to find the volume of the solid
SI unit of length is meter
255cm=2550mm and 2.55m
about the scientists question: it'll be impossible to carry out experiments as science has to be very precise
1kg=1000g
1 fahrenheit = -17.2 degree celsius
milliliter

hope it helps :) need anything just msg

3 0

3 years ago