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Nadusha1986 [10]
3 years ago
10

Given the results of your coarse titration, how does the concentration of the acetic acid compare to the concentration of sodium

hydroxide?
a. The acetic acid solution has the same molarity as the sodium hydroxide solution.
b. The acetic acid solution has a lower molarity than the sodium hydroxide solution.
c. The concentration of the acetic acid solution cannot be determined.
d. The acetic acid solution has a higher molarity than the sodium hydroxide solution.
Chemistry
1 answer:
ratelena [41]3 years ago
5 0

Answer:

d. The acetic acid solution has a higher molarity that the Sodium Hydroxide solution.

Explanation:

Sodium Hydroxide is also known as caustic soda. It is an inorganic compound with molar mass of 39.997 g/mol. It is soluble in water, ethanol and Methanol.  Its formula is NaOH.

Acetic acid is a colorless organic compound liquid called ethanoic acid. It has molar mass of 60.052 g/mol. It is soluble in water. Its formula is CH3COOH.

The molarity of acetic acid is higher than sodium hydroxide.

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Answer is: 2. dillute acids feel slipper.

1) Acids are corrosive is correct. For example hydrochloric acid (HCl) will react with most metals.

2) Dillute acids feel slippery is not correct. Bases, for example solution of sodium hydroxide feels slipery.

3) Acids have a distinctly sour taste is correct. For example, vinegar is mixture of acetic acid (CH₃COOH) and water (H₂O). Vinegar is colourless liquid with sour taste and pungent smell, freezing point of the vinegar is lower than glacial acetic acid.

4) Acids have more hydronium ions than hydroxide ions is correct. Because acid gives a lot of hydrogen cations (H⁺), pH (pH = -log[H⁺]) is lower than seven (acidic solution).

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3 years ago
11) Predict the products of this reaction.
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Explanation:

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2 years ago
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Describe the composition of the nucleus of an atom.
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3 0
3 years ago
If you feed 100 kg of N2 gas and 100 kg of H2 gas into a
torisob [31]

Answer : The mass of ammonia produced can be, 121.429 k

Solution : Given,

Mass of N_2 = 100 kg  = 100000 g

Mass of H_2 = 100 kg = 100000 g

Molar mass of N_2 = 28 g/mole

Molar mass of H_2 = 2 g/mole

Molar mass of NH_3 = 17 g/mole

First we have to calculate the moles of N_2 and H_2.

\text{ Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molar mass of }N_2}=\frac{100000g}{28g/mole}=3571.43moles

\text{ Moles of }H_2=\frac{\text{ Mass of }H_2}{\text{ Molar mass of }H_2}=\frac{100000g}{2g/mole}=50000moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

N_2+3H_2\rightarrow 2NH_3

From the balanced reaction we conclude that

As, 1 mole of N_2 react with 3 mole of H_2

So, 3571.43 moles of N_2 react with 3571.43\times 3=10714.29 moles of H_2

From this we conclude that, H_2 is an excess reagent because the given moles are greater than the required moles and N_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of NH_3

From the reaction, we conclude that

As, 1 mole of N_2 react to give 2 mole of NH_3

So, 3571.43 moles of N_2 react to give 3571.43\times 2=7142.86 moles of NH_3

Now we have to calculate the mass of NH_3

\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3

\text{ Mass of }NH_3=(7142.86moles)\times (17g/mole)=121428.62g=121.429kg

Therefore, the mass of ammonia produced can be, 121.429 kg

6 0
3 years ago
Help pleaseeeeeeeeeee
hichkok12 [17]

Answer:

D 1 and 3 only I am not sure

Explanation:

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