Answer:
a.
ZnS(s) + O2(g) → ZnO(s) + SO2(g)
b.
HCl (aq) + Ba(OH)2(aq) → BaCl2(aq) + H2O
C. Primary consumers
Explanation:
Producers are like grass, herbivore is like a cricket and primary consumers is like a bird
the molar mass of the element is 81.36 g/mol
<u><em>calculation</em></u>
step 1 : multiply each %abundance of the isotope by its mass number
that is 79.95 x 29.9 =2391
81.95 x 70.1 = 5745
Step 2: add them together
2390.5 + 5744.7 =8136
Step 3: divide by 100
= 8136/100 = 81.36 g/mol
Answer:
I was traveling on a train where I fell asleep. someone stole my luggage in which I had money and other essentials. when the ticket checker arrived a lady paid my fine. she helped me a lot. when I told her about being robbed she helped me and took me to the police station and I found my bag. I insisted she take the money she paid for my fine but she said that in return you too help someone."I have never found such a kind person ever since.".....
Explanation: I think this is what you are looking for. Hope this helps.
To determine the volume of both concentration of vinegar, we need to set up two equations since we have two unknowns.
For the first equation, we do a mass balance:
mass of 100% vinegar + mass of 13% vinegar = mass of 42% vinegar
Assuming they have the same densities, then we can write this equation in terms of volume.
V(100%) + V(13%) = V(42%)
we let x = V(100%)
y = V(13%)
x + y = 150
For the second equation, we do a component balance:
1.00x + .13y = 150(.42)
x + .13y = 63
The two equations are
x + y = 150
x + .13y = 63
Solving for x and y,
x = 50
y = 100
Therefore, you need to mix 50 mL of the 100% vinegar and 100 mL of the 13% vinegar.
