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Law Incorporation [45]
3 years ago
9

What is asubstance that flows Called

Chemistry
2 answers:
o-na [289]3 years ago
8 0
It is called liquid
madam [21]3 years ago
6 0
It is called a liquid
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HELP ASAP PLEASE WHAT IS THIS ANSWER
JulijaS [17]

Answer:

im pretty sure its c

Explanation:

6 0
3 years ago
Read 2 more answers
How many moles is 3.85 x 1025 atoms of gold?
IrinaK [193]

Answer:

64.17 Moles of Au

Explanation:

(atoms and particles are the same)

3.85 x 10 ^25 x (1 mol              

                         /6.02 x 10^23)

3.85 / 6 = .64166

.6416 x 10^2 = 64.166

If you round up the answer you will get 64.17

64.17  moles of Au

4 0
2 years ago
Read 2 more answers
The only nonmetal in Group 14 is<br> A carbon.<br> B. oxygen.<br> C. nitrogen.<br> D. fluorine.
lesantik [10]

Answer:

carbon

Explanation:

i just googled it

4 0
2 years ago
Nitrogen dioxide (NO2) cannot be obtained in a pure form in the gas phase because it exists as a mixture of NO2 and N2O4. At 16°
Pavel [41]

Answer:

PNO₂ = 0.49 atm

PN₂O₄ = 0.45 atm

Explanation:

Let's begin with the equation of ideal gas, and derivate from it an equation that  involves the density (ρ = m/V).

PV = nRT

n = m/M (m is the mass, and M the molar mass)

PV = \frac{m}{M}RT

PxM = \frac{m}{V}RT

PxM = ρRT

ρ = PxM/RT

With the density of the gas mixture, we can calculate the average of molar mass (Mavg), with the constant of the gases R = 0.082 atm.L/mol.K, and T = 16 + 273 = 289 K

2.7 = \frac{0.94xMavg}{0.082x289}

0.94Mavg = 63.9846

Mavg = 68.0687 g/mol

The molar mass of N is 14 g/mol and of O is 16 g/mol, than M_{NO2} = 46 g/mol and M_{N2O4} = 96 g/mol. Calling y the molar fraction:

Mavg = M_{NO2}y_{NO2} + M_{N2O4}y_{N2O4}

And,

y_{NO2} + y_{N2O4} = 1

y_{N2O4} = 1 - y_{NO2}

So,

68.0687 = 46y_{NO2} + 92x(1 - y_{NO2})

68.0687 - 92 = 46y_{NO2} - 92y_{NO2}

46y_{NO2} = 23.9313

y_{NO2} = 0.52

y_{N2O4} = 0.48

The partial pressure is the molar fraction multiplied by the total pressure so:

PNO₂ = 0.52x0.94 = 0.49 atm

PN₂O₄ = 0.48x0.94 = 0.45 atm

8 0
3 years ago
Calcium hydroxide is titrated with nitric acid. What volume of 0.0200 M calcium hydroxide is required to neutralize 35.00 ml of
gogolik [260]

Answer:

43.75 ml

Explanation:

Given that the equation of the reaction is;

2HNO3(aq) + Ca(OH)2(aq) ---> Ca(NO3)2(aq) + 2 H20(l)

Concentration of acid CA= 0.05 M

Concentration of base CB = 0.02 M

Volume of acid VA = 35.00ml

Volume of base VB= ???

Number of moles of acid NA= 2

Number of moles of base NB=1

From

CAVA/CBVB= NA/NB

Making VB the subject of the formula;

VB= CAVANB/CBNA

VB= 0.05 × 35 × 1/ 0.02 × 2

VB=1.75 /0.04

VB= 43.75 ml

8 0
3 years ago
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