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Law Incorporation [45]
3 years ago
9

What is asubstance that flows Called

Chemistry
2 answers:
o-na [289]3 years ago
8 0
It is called liquid
madam [21]3 years ago
6 0
It is called a liquid
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What is the total anion concentration (in meq/l) of a solution that contains 6.0 meq/lna+ , 11.0 meq/lca2+ , and 3.0 meq/lli+ ?
Oliga [24]
<span>Answer: The total anion concentration = 6.0 + 2x12.0 + 3.0 = 33.0mEq/L</span>
7 0
3 years ago
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Is cutting grass of physical change or chemical change
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Answer:

physical

Explanation:

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4 years ago
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How many total moles of ions are released when the following sample dissolves completely in water?
pogonyaev

Answer:

                      8.55 × 10²⁴ Ions

Explanation:

                    Ammonium Chloride is an ionic compound which contains a monatomic anion (Cl⁻ ; Chloride) and a polyatomic cation (NH₄⁺ ; Ammonium).

Hence, when added in water Ammonium Chloride ionizes as;

                                      NH₄Cl   →    NH₄⁺  +  Cl⁻

Hence, we can say that it produces two ions when dissolved in water.

Also,

We know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of ions  contained by 7.1 moles of NH₄Cl, we will use following relation to first calculate the number of molecules as;

          Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Molecules,

          Number of Molecules  =  Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting values,

          Number of Molecules  =  7.1 mol × 6.022 × 10²³

          Number of Molecules  =  4.27 × 10²⁴ Molecules

So,

As,

                         1 Molecule of NH₄Cl contained  =  2 Ions

So,

              4.27 × 10²⁴ Molecules of NH₄Cl will contain  =  X ions

Solving for X,

                     X =  2 Ions × 4.27 × 10²⁴ Molecules / 1 Molecule

                    X =  8.55 × 10²⁴ Ions

8 0
3 years ago
What volume of 1.10 M SrCl2 is needed to prepare 525 mL of 5.00 mM SrCl2?
grigory [225]

Answer:- 2.39 mL are required.

Solution:- It's a dilution problem and to solve this type of problems we use the dilution equation:

M_1V_1=M_2V_2

Where, M_1 and M_2 are molarities of concentrated and diluted solutions and V_1 and V_2 are their respective volumes.

M_1 = 1.10M

M_2 = 5.00mM = 0.005M    (since, mM stands for milli molar and M stands for molar. 1M = 1000mM)

V_1 = ?

V_2 = 525 mL

Let's plug in the given values in the formula:

1.10M(V_1)=0.005M(525mL)

V_1=(\frac{0.005M*525mL}{1.10M})

V_1=2.39mL

So, 2.39 mL of 1.10M are needed to make 525 mL of 5.00mM solution.

7 0
3 years ago
How does changing the concentration of the reactants change the parts of a rate law? It changes the rate, R. It changes the rate
Sidana [21]

Answer

A. It changes the rate, R

Explanation

When we change the concentration of the reactants in a chemical reaction, it affects the rate of reaction that happens in the process. Typically, the rate of reaction will decrease with time if the concentration of the reactants decreases because the reactants will be converted to products. Similarly, the rate of reaction will increase when the concentration of reactants are increased.

4 0
3 years ago
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