Question

2.00 moles of an ideal gas was found to occupy a volume of 17.4L at a pressure of 3.00 atm and at a temperature of 45 C. Calulate the value of the cas constant R in

Answer 1

Answer:

$0.082 atm L mol^{-1} K^{-1}$

Explanation:

The pressure, the volume and the temperature of an ideal gas are related to each other by the equation of state:

$pV=nRT$

where

p is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the absolute temperature

For the gas in this problem:

n = 2.00 mol is the number of moles

V = 17.4 L is the gas volume

p = 3.00 atm is the gas pressure

$T=45C+273=318 K$ is the absolute temperature

Solving for R, we find the gas constant:

$R=\frac{pV}{nT}=\frac{(3.00)(17.4)}{(2.00)(318)}=0.082 atm L mol^{-1} K^{-1}$