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3 years ago

A balloon is filled with 3.8 l of helium gas at stp. approximately how many moles of helium are contained in the balloon?

Chemistry

2 answers:

love history [14]3 years ago

7 0

Hope this helps you.

Lelechka [254]3 years ago

3 0

Answer:

0.16964 moles ≈ 0.17 moles

Explanation:

At STP, one mole of a gas has a volume of 22.4 L.

1 mole = 22.4L

x mole = 3.8L

x = ( 3.8 * 1 ) / 22.4

x = 3.8 / 22.4

x = 0.16964 moles ≈ 0.17 moles

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nevsk [136]

Answer:

5 significant figures

Explanation:

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A powder sample weighing 250 g and having a surface area of 1 m2/g is dispersed in 1 L of water. After 10 minutes, 0.4 g of the

lisabon 2012 [21]

Answer:

$K = 2.64 * 10^{-8}$

$15 \frac{5}{8}$ hours

Explanation:

Given

Surface Area (S) of 250 grams of powder sample $= 250$ square meter.

$S = 2500000$ square centimeter

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$V\frac{dC}{dT} = \frac{dM}{dT} = \frac{0.40*60}{10} = 0.66$ mg per second

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$\frac{dM}{dT} = K SC_s$

$0.66 = K* 2500000* 10\\$

$K = 2.64 * 10^{-8}$ cm /sec

b) Time taken

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$\frac{10*60}{0.4} * 37.5 = 56,250$

Time in hours

$15 \frac{5}{8}$ hours

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Does the coating from another type of candy dissolve in water like M&M’s ?

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