The tension in rope C is determined as 122.23 N.
<h3>Tension in rope C</h3>
The tension in rope C is calculated as follows;
B² = A² + C²
C² = B² - A²
C² = (752²) - (742²)
C² = 14,940
C = √14,940
C = 122.23 N
Thus, the tension in rope C is determined as 122.23 N.
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Answer:
thw temperature of the male will be higher than that of the female.
The experiments will involve two billiard balls of known masses, m₁ and m₂, and velocities u₁ and u₂. The two are allowed to collide and the velocities of the balls after the collision v₁ and v₂ are recorded.
The momentum before and after the collision is then calculated as follows:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
<h3>What is the statement of the law of conservation of momentum?</h3>
The law of the conservation of momentum states that the momentum before and after collision in a system of colliding bodies is conserved
The momentum of a body is calculated using the formula below:
Momentum = mass * velocity.
Hence, for the two billiard balls, the momentum before and after the collision is conserved.
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Answer:
E = 2.5 x 10⁻¹⁴ J
Explanation:
given,
diameter = 1.33 x 10⁻¹⁴ m
mass = 6.64 x 10⁻²⁷ kg
wavelength is equal to diameter
de broglie wavelength equal to diameter



v = 7.5 x 10⁶ m/s
Kinetic energy is equal to


E = 2.5 x 10⁻¹⁴ J
Answer:
The value of the average convection coefficient is 20 W/Km².
Explanation:
Given that,
For first object,
Characteristic length = 0.5 m
Surface temperature = 400 K
Atmospheric temperature = 300 K
Velocity = 25 m/s
Air velocity = 5 m/s
Characteristic length of second object = 2.5 m
We have same shape and density of both objects so the reynold number will be same,
We need to calculate the value of the average convection coefficient
Using formula of reynold number for both objects



Here, 


Put the value into the formula


Hence, The value of the average convection coefficient is 20 W/Km².