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3 years ago

Which two factors does the power of a machine depend on?

Physics

1 answer:

lianna [129]3 years ago

7 0

The power of a machine depend on two factors are work and time.

Option C

<u>Explanation:</u>

In science, power defined as the amount of work done in a unit time. i.e. delivering work in a rate of time or energy supply, expressed in input of work or transmitted energy divided by the time interval (t) or W/t.

Example: Some work can be done in the long run with a low-power engine or in a short time with a motor with high performance. The equation for power can be given as

$Power\ (in\ watts) =\frac{\text { work (joules) }}{\text { time (seconds) }}$

$P=\frac{W}{t}$

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A coil consisting of 50 turns of wire is powered by a 9V battery. If the coil draws 1.5 A from the battery, what is the MMF, in

aivan3 [116]

A. 75 ampere-turns

<u>Explanation:</u>

Given:

Number of turns, n = 50

Voltage, V = 9V

Current, I = 1.5A

MMF= ?

MMF is magnetomotive force.

MMF is independent on voltage and dependent on the number of turns and current in the wire.

Thus, MMF can be written as:

$MMF = nI$

On substituting the value we get:

MMF = 50 X 1.5

MMF = 75 ampere-turns

7 0

3 years ago

When the input work on simple machine equals the work the machine is said to be 100% efficient

Semmy [17]

Answer:

This is not a question, but a statement. The concept that the work done is equal to the input work on a simple machine is called ideal machine. An ideal machine has 100% efficiency which means that there is no loss. All the amount of input work is equal to the useful output of the machine.

Explanation:

8 0

3 years ago

What process makes this pattern on the ocean floor?

Katen [24]

Plate tectonics

and the ocean floor
Bathymetry, the shape of the ocean floor, is largely a result of a process called plate tectonics.

please give me brainliest

4 0

3 years ago

4. What is the best estimate of the frequency of the wave shown below?

tatyana61 [14]

Answer:

The answer is "Option D"

Explanation:

Please find the graph file in the attached file.

Using formula:

$\to v= \rho \lambda \\\\\ \to \lambda= 130 \cm \\\\ \to v= 335 \frac{cm}{s}\\\\ \to \rho= \frac{v}{\lambda} \\\\$

$=\frac{335}{130} \\\\ = 2.57 \approx 2.50 \ Hz$

7 0

3 years ago

Glider A of mass 2.5 kg moves with speed 1.7 m/s on a horizontal rail without friction. It collides elastically with glider B of

omeli [17]

Answer:

The speed of glider A after the collision is 0 m/s

Explanation:

Hi there!

The two gliders collide elastically. That means that the kinetic energy and momentum of the system are conserved, i.e., they remain constant before and after the collision.

The momentum is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass.

v = velocity.

The equation of kinetic energy is the following:

KE = 1/2 · m · v²

Where:

KE = kinetic energy.

m = mass.

v = velocity.

The momentum of the system is the sum of the momentum of each glider.

be:

mA = mass of glider A

mB = mass of glider B

vA = velocity of glider A before the collision.

vB = velocity of glider B before the collision.

vA´= velocity of glider A after the collision.

vB´= velocity of glider B after the collision.

The momentum of the system will be:

mA · vA + mB · vB = mA · vA´ + mB · vB´

Replacing with the given data:

2.5 kg · 1.7 m/s + 2.5 kg · 0 m/s = 2.5 kg · vA´ + 2.5 kg · vB´

divide both sides of the equation by 2.5 kg:

1.7 m/s = vA´ + vB´

1.7 m/s - vA´ = vB´

Using the conservation of the kinetic energy of the system we can find vA´:

1/2 · mA · vA² + 1/2 · mB · vB² = 1/2 · mA · vA´² + 1/2 · mB · (1.7 m/s - vA´)²

Let´s replace with the given data:

1/2 · 2.5 kg · (1.7 m/s)² + 0 = 1/2 · 2.5 kg · vA´² + 1/2 · 2.5 kg · (1.7 m/s - vA´)²

divide both sides of the equation by (1/2 · 2.5 kg):

(1.7 m/s)² = vA´² + (1.7 m/s - vA´)²

(1.7 m/s)² = vA´² + (1.7 m/s)² - 2· 1.7 m/s · vA´ + vA´²

0 = 2vA´² - 2· 1.7 m/s · vA´

0 = 2vA´(vA´ - 1.7 m/s)

vA´ = 0

vA´ - 1.7 m/s = 0

vA´ = 1.7 m/s

Since the velocity of the glider A after the collision can´t be the same as before the collision, the velocity of glider A after the collision is 0 m/s.

4 0

3 years ago