The force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity is known as weight.
Weight is the force of gravity acting on a body.
The formula is :
W =mg
Here,
W is the weight or force acting on the body. m is the mass of the body, and g is the gravitational acceleration.
Since weight is also a force, so its SI unit is also newton. The value of weight varies from place to place depending on the gravity. Its value can also be equal to zero.
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The momentum before is zero because nothing is moving. Note that because momentum is a conserved vector, the total momentum after the shot is also zero. You just have to add the products of mass and velocity in opposite directions. So the answer is zero
Answer:
Relation between initial speed of bullet and height h is given as

Explanation:
As we know that system of block and bullet swings up to height h after collision
So we have

so we have

so speed of the block + bullet just after the impact is given by above equation
Now we also know that there is no force on the system of bullet + block in the direction of motion
So we can use momentum conservation

now we have

The position of the object at time t =2.0 s is <u>6.4 m.</u>
Velocity vₓ of a body is the rate at which the position x of the object changes with time.
Therefore,

Write an equation for x.

Substitute the equation for vₓ =2t² in the integral.

Here, the constant of integration is C and it is determined by applying initial conditions.
When t =0, x = 1. 1m

Substitute 2.0s for t.

The position of the particle at t =2.0 s is <u>6.4m</u>