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shtirl [24]
3 years ago
8

A 410-kg piano is being unloaded from a truck by rolling it down a ramp inclined at 25°. There is negligible friction and the ra

mp is 11.0 m long. Two workers slow the rate at which the piano moves by pushing with a combined force of 1300 N parallel to the ramp.If the piano starts from rest, how fast is it moving at the bottom?
Physics
1 answer:
SpyIntel [72]3 years ago
5 0

Answer:BOONK GANG

Explanation:

AHAHAHA I USE CALC LIKE IN CLASS AHAHA

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5lbs is greater.
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a closed tank is partially filled with glycerin. if the air pressure in the tank is 6 lb/in.2 and the depth of glycerin is 10 ft
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3 years ago
In what ways do people use natural resources? What problems does use of those resources cause?
Lunna [17]

Answer:

The Challenges of Using Natural Resources

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4 0
3 years ago
If you are driving 95 km????h along a straight road and you look to the side for 2.0 s, how far do you travel during this inatte
Gala2k [10]

Answer:

52.7 m

Explanation:

Given that

speed of the vehicle, v = 95 km/h

time of inattentiveness, t = 2 s

distance travelled, s = ?

Since we have the speed in km/h and the time in s, it would be best if we converted one of them to make sure we have all units in the same rank.

95 km/h = 95 * 1000/3600 m/s

95 km/h = 95000/3600 m/s

95 km/h = 26.38 m/s

Now, we use our derived speed in m/s

Speed of a moving vehicle is given by,

v = s/t, where

v = speed in m/s

s = distance travelled, in m

t = time spent, in s

if we make d the subject of formula by rearranging the equation, we have

s = v * t

distance travelled, s = 26.38 * 2

distance travelled, s = 52.7 m

therefore, during this inattentive period, 52.7 m was travelled.

3 0
2 years ago
Rahul has 2 bulbs connected across two cells in a simple circuits shown. How can he make the bulbs glow dimmer?
Ray Of Light [21]

Answer:

in the parallel connection the light bulbs shine less than in the series connection

Explanation:

In a series circuit the current through the whole circuit is the same, therefore the power (brightness) of each bulb is

           P = i² R

where R is the resistance of each bulb and i the current of the circuit.

If we connect the light bulbs and the cells in parallel, the current in the circuit is the sum of the east that passes through each light bulb,

            i = i₁ + i₂

if the two light bulbs are the same

           i = 2 i₁

           i₁ = i / 2

so the power of each bulb is is

           P = i₁² R

           P = R i² / 4

           P = ¼ P_initial

Therefore we see that in the parallel connection the light bulbs shine less than in the series connection

3 0
3 years ago
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