Answer: The height of the fluid rise is 0.01m
Explanation:
Using the equation
h = (2TcosѲ )/rpg
h= height of the fluid rise
diameter of the tube =3mm
radius of the tube= 3/2 =1.5mm=0.0015
T= surface tension = 600mN/m=0.6N/m
Ѳ = contact angle = 
C
p= density =3.7g/cm3= 3700kg/m3
g= acceleration due to gravity =9.8m/s2
h = ( 2*0.6*0.5)/(0.0015*3700*9.8)
h = 0.6/54.39
h= 0.01m
Therefore,the height of the fluid rise is 0.01m
The answer is it will supply 1.1 x 10⁹ J of energy each second.
we can calculate this by using the following equation;
P = W/t
<span>W = P x t
</span><span>and by work energy relation;
E = W = P x t
</span>1 watt = 1j/s
1megawatt = 1000000 = 10⁶ j/s
<span>E = 1100 x 106 x 1 </span>
E = 1.1 x 10⁹ J
Answer:
Explanation:
Kinematics equation for constant acceleration:
Answer: I think the answer is d
Explanation: sry if wrong
When a gas is inside the tube, the individual air molecules travel the length of the tube.
<h3>What is molecules?</h3>
The individual particle of a gas element moving randomly inside the element structure.
When the gas contained in a container, the molecules move randomly inside it. According to the kinetic theory of gases, molecules travel the mean distance. The air molecules vibrates horizontally parallel to the length of the tube.
In an open tube, air molecules are distant from each other. So, they can travel the length of the tube.
Thus, individual air molecules travel the length of the tube.
Learn more about molecules.
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