Answer:
The best angular magnification is
-375
Explanation:
Fe = Fo - L
From the question, (Fo) = 1.08 cm while (L) = 0.56cm
Thus, Fe = 1.08 - 0.56 = 0.52cm
Now, let's apply the angular magnification equation ;
M = - Di/Do
Where Di is the distance from the lens to the image and Do is the distance of the object to the lens.
In this question, Di is represented by f which is the distance from the lens to the image and it is f= 195cm
Also,Do is represented by Fe which is 0.52cm and it is the distance of the object to the lens.
Thus m = - f/fe = - 195/0.52 = - 375
Answer: 10.02m
Explanation: Given
M1 = 26.3kg
M2 = 52.5kg
d = 5m
If the systems centre of mass does not change, the two skaters will definitely meet at the centre of mass.
If the 26.3kg skater is a m away from the centre of the mass, then the 52.5kg skater is (5-a) m away from the centre of the mass. Thus,
M1a + M2(5-a) = 0
26.3a + 52.5(5-a) = 0
26.3 a + 262.5 - 52.5a = 0
-26.2a + 262.5 = 0
26.2a = 262.5
a = 262.5/26.2
a = 10.02m
Answer:
see that there is no dependence on speed, so the work remains constant
Explanation:
Work is defined by the expression
W = F. d
where the boldface indicates vectors, this equation can be written in scalar form
W = f d cos θ
where θ is the angle between force and displacement.
We see that there is no dependence on speed, so the work remains constant
The power is
P = W / t
P = f d / t
p = F v
we see that the power is the one that depends on the speed of the body
Answer:
Explanation:
<u>Given:</u>
No. of times = 600 times
Time = 60 seconds
<u>Required:</u>
Frequency = f = ?
Time Period = T = ?
<u>Solution:</u>
<h2>Frequency = No. of Times / Time</h2>
Frequency = 600 / 60
<u>Frequency = 10 Hz</u>
<h2>Time Period = 1 / Frequency</h2>
Time Period = 1 / 10
<u>Time Period = 0.1 secs</u>
