All categories

3 years ago

how much energy is required to move a 4.00-microcoulomb charge through a potential difference of 36.0 volts?

Physics

1 answer:

musickatia [10]3 years ago

4 0

Answer:

All you gotta do is search it up. ask the same question you asked on here, type it into google, it'll teach you a lot more than your actual teachers.

Explanation:

You might be interested in

A chipmunk with a mass of 2 kg sits on a branch that is 10 m off the ground.

vlada-n [284]

I hope I'm not too late.

GPE = mass * gravity * height

GPE = 2 kg * 9.8 m/s * 10

GPE = 196 Joules

3 0

2 years ago

In a "Rotor-ride" at a carnival, people rotate in a vertical cylindrically walled "room." If the room radius is 5.5 m, and the r

Crank

Answer:

0.181

Explanation:

We can convert the 0.5 rps into standard angular velocity unit rad/s knowing that each revolution is 2π:

ω = 0.5 rps = 0.5*2π = 3.14 rad/s

From here we can calculate the centripetal acceleration

$a_c = \omega^2r = 3.14^2*5.5 = 54.3 m/s^2$

Using Newton 2nd law we can calculate the centripetal force that pressing on the rider, as well as the reactive normal force:

$F = N = a_cm = 54.3 m$

Also the friction force and friction acceleration

$F_f = N\mu = 54.3 m \mu N$

$a_f = F_f / m = 54.3 \mu$

For the rider to not slide down, friction acceleration must win over gravitational acceleration g = 9.81 m/s2:

$g = a_f = 54.3 \mu$

$9.81 = 54.3 \mu$

$\mu = 9.81 / 54.3 = 0.181$

6 0

2 years ago

Un leopardo recorre 12.000 yardas, el tigre recorre 1.096.800 centímetros y un puma recorre 10,968 kilómetros. ¿Cuál de los tres

Maksim231197 [3]

El leopardo hizo el mayor recorrido.

7 0

2 years ago

You can, in an emergency, start a manual transmission car by putting it in neutral, letting the car roll down a hill to pick up

Anna [14]

Answer:

The hill should be not less than 0.625 m high

Explanation:

This problem can be solved by using the principle of conservation of mechanical energy. In the absence of friction, the total mechanical energy is conserved. That means that

$E_m=U+K$ is constant, being U the potential energy and K the kinetic energy

$U=mgh$

$K=\frac{mv^2}{2}$

When the car is in the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.

The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.

$mgh=\frac{mv^2}{2}$

We can solve for h:

$h=\frac{v^2}{2g}=\frac{3.5^2}{2(9.8)}=0.625m$

The hill should be not less than 0.625 m high

8 0

2 years ago

You connect five identical resistors in series to a battery whose EMF is 12.0 V and whose internal resistance is negligible. You

avanturin [10]

Answer:

The resistance of each resistor is 2.5 Ω

The potential difference across each resistor is 2.4 V.

Explanation:

By Ohm's law,

V = IR

where V is the potential difference or voltage across an element, I is the current flowing through it and R is its effective resistance.

For the group of five resistors, let their combined resistance be R.

Then

(12.0 V) = (0.961 A)(R)

$R = \dfrac{12}{0.961}\,\Omega$

Because they are in series, R is the arithmetic sum of their individual resistances. Because they are all identical, the resistance of each resistor is

$= \dfrac{12}{5\times0.961}\,\Omega = 2.5\,\Omega$

Also, because they are in series and are equal, the EMF is distributed across them equally. Therefore, the potential difference across each resistor is

$\dfrac{12.0\text{ V}}{5} = 2.40\text{ V}$

4 0

3 years ago

Read 2 more answers