Okay ! :) cool wait what this suppose to be a question?
A function will not have any repeating x values...they all have to be different. They can have repeating y values, just not the x ones.
so ur sets of numbers are all set up like (x,y). Now look through ur answer choices and which one has all different x values ? That will be ur function.
ur answer is : { (-4,-3), (0,-3), (1,-3), (4,-3)}.....and as u can see, all the x values {-4,0,1,4} are different.
Hello from MrBillDoesMath!
Answer:
Your answer is correct. (You have earned the unofficial title of Genius, Jr. );
Discussion:
Whew! This is a long problem. Let me see what I get and compare it to your answer. First each of the 3 terms contains the sqrt(yz) so let's factor that terms out. You equations equals
sqrt(yz) ( sqrt(108) + 3 sqrt(98) + 2 sqrt(75) ) (A)
Hmm.... let's look at the prime factorizations....
108 = 3 * 36 = 3 * (4*9) = 3 * 2^2* 3^2
98 = 2 * 49 = 2 * 7^2
75 = 3 * 25 = 3 * 5^2
So (A) =
sqrt(yz) ( 6 sqrt(3) + 3*7 sqrt(2) + 2*5 sqrt(3) ) =
sqrt(yz) ( ( 6 + 2*5) sqrt(3) + 21 sqrt(2) ) =
sqrt(yz) ( (6 + 10) sqrt(3) + 21 sqrt(2)) =
sqrt(yz) ( 16 sqrt(3) + 21 sqrt(2) )
Our answers agree!
Thank you,
MrB
1. 0.32
2. 5/12
3. 1/2
4. 8/9
hope this helps :)
brainliest?
your answer is 0
Step-by-step explanation:
