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kupik [55]
4 years ago
6

An especially violent lightning bolt has an average current of 1.89 x 103 A lasting 0.133 s. How much charge is delivered to the

ground by the lightning bolt?
Physics
1 answer:
Rasek [7]4 years ago
3 0
<h2> Charge = 25.9 Ampsec^{-1}</h2>

Explanation:

Given,

The average current (I) = {1.89} \times {103 A} and

Time period (T) = 0.133 s

The charge is calculated by multiplying the current to the time period.

Hence,

To find, the charge delivered to the ground by the lightning bolt(Q) = ?

By applying the formula of charge that is-

Charge(Q) = Current(I) \times Time(T)

∴ Charge(Q) = {1.89} \times {103 A}\times 0.133 s

= 25.89111 As^{-1}

= 25.9 As^{-}

<h3>Thus, the charge of 25.9 Ampsec^{-1} is delivered to the ground by the lightning bolt.</h3>
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Answer:

B=μ₀I/2r

Explanation:

Produced magnetic field due to an existing electric field through a coil or conductor can be explained by Biot-Savart Law. Formula for this law is:

dB=(μ₀I/4π.r²)dL

Here,

r=Radius of the loop

I and r are constants with respect to length L.

To convert linear displacement L into angular displacement Ф:

dL=r.dФ

So,

dB=(μ₀I/4π.r²)r.dФ

dB=(μ₀I/4π.r)dФ

Integrating both sides over the circle i.e. from 0 radians to 2π radians  (360⁰), while the integration will apply only on dФ as all others are constants.

B=(μ₀I/4πr)(2π-0)

<u>B=(μ₀I/2r)</u>

3 0
4 years ago
2. Two people, one on Earth and the other on the Moon, try and lift 200 kg blocks. Which person
Art [367]

Answer:

The person on Earth will have to exert more force to lift their block

Explanation:

The mass of the blocks to be lifted = 200 kg

The location of the first person = On Earth

The location of the second person = On the Moon

The force a person will have to exert to lift the block = The weight of the block = The gravitational force, F, on the block which is given as follows;

F = \dfrac{G \times M_1}{R^2}  \times m_2

Where;

\dfrac{G \times M_1}{R^2}= The acceleration due to gravity on the Earth or the Moon, depending on the location of the block

m₂ = The mass of the block

Therefore, given that the acceleration due to gravity on the Earth is larger than the acceleration due to gravity on the Moon, the weight of the block on the Earth is larger than the weight of the block on the Moon, and the person on Earth have to exert more force to lift the heavier weight of the block on Earth than the person on the Moon will have to exert to lift the same block as the block has a lower weight on the Moon due to lower acceleration due to gravity on the Moon.

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3 years ago
A stubborn 130 kg pig sits down and refuses to move. to drag the pig to the barn, the exasperated farmer ties a rope around the
TEA [102]
<span>Unless the pig moves static friction acts on it once the pig starts moving kinetic friction comes in to play so when the pig is not moving=frictional force acting on it =normal force*co-efficient of static friction.</span>
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4 years ago
Using the following equation, find in seconds 145m = 9 m/s x t-35m
Zina [86]

Answer:

t = 20 s

Explanation:

145 m = 9 m/s × t – 35m

We can obtain the value of t in seconds by doing the following:

145 m = 9 m/s × t – 35m

Add 35 m to both side as shown below:

145 m + 35 m = 9 m/s × t – 35m + 35 m

180 m = 9 m/s × t

Divide both side by 9 m/s

t = 180 m / 9 m/s

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Therefore, the value of t is 20 seconds.

5 0
3 years ago
A horizontal spring with stiffness 0.4 N/m has a relaxed length of 11 cm (0.11 m). A mass of 21 grams (0.021 kg) is attached and
riadik2000 [5.3K]

Answer:

0.6983 m/s

Explanation:

k = spring constant of the spring = 0.4 N/m

L₀ = Initial length = 11 cm = 0.11 m

L = Final length = 27 cm = 0.27 m

x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m

m = mass of the mass attached = 0.021 kg

v = speed of the mass

Using conservation of energy

Kinetic energy of mass = Spring potential energy

(0.5) m v² = (0.5) k x²

m v² = k x²

(0.021) v² = (0.4) (0.16)²

v = 0.6983 m/s

5 0
4 years ago
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