Answer:
448 meters
Explanation:
every second it moves 8 meters, so all you have to do is multiply 56x8 or 8x56 either way it is the same thing and you will get the same answer
Static Friction
It is the friction that exists between a stationary object and the surface on which it's resting.
Sliding friction
It is the resistance created by two objects sliding against each other.
Rolling friction:-
It is the force resisting the motion when a body rolls on a surface.
hope this helps x
La longitud <em>final</em> del puente de acero es 100.018 metros.
Asumamos que la dilatación <em>térmica</em> experimentada por el puente de acero es <em>pequeña</em>, de modo que podemos emplear la siguiente aproximación <em>lineal</em> para determinar la longitud <em>final</em> del puente de acero (
), en metros:
(1)
Donde:
- Longitud inicial del puente, en metros.
- Coeficiente de dilatación, sin unidad.
- Temperatura inicial, en grados Celsius.
- Temperatura final, en grados Celsius.
Si tenemos que
,
,
y
, entonces la longitud final del puente de acero es:
![L = (100\,m)\cdot [1+(11.5\times 10^{-6})\cdot (24\,^{\circ}C - 8\,^{\circ}C)]](https://tex.z-dn.net/?f=L%20%3D%20%28100%5C%2Cm%29%5Ccdot%20%5B1%2B%2811.5%5Ctimes%2010%5E%7B-6%7D%29%5Ccdot%20%2824%5C%2C%5E%7B%5Ccirc%7DC%20-%208%5C%2C%5E%7B%5Ccirc%7DC%29%5D)

La longitud <em>final</em> del puente de acero es 100.018 metros.
Para aprender más sobre dilatación térmica, invitamos cordialmente a ver esta pregunta verificada: brainly.com/question/24953416
Answer:
The distance s of how far the ball will go at the highest setting = 2.25m
Explanation:
Let consider x to be the representative of the compression and the distance to be s
Recall that:

By cross multiplying




Thus, for the first setting
x = 1 , s = 0.25
for the second setting
x = 2, s = 1
1 = 0.25A + B --- (1)
4 = A + B ----- (2)
From (1); let B = 1 - 0.25A and substitute it into (2)
4 = A + 1 - 0.25 A
4 - 1 = A - 0.25 A
3 = 0.75 A
A = 3/0.75
A = 4
From (2)
4 = A + B
4 = 4 + B
B = 4 - 4
B = 0
Therefore, for the highest setting, where x = 3
Then :
will be:
3² = 4s + 0
9 = 4s
s = 9/4
s = 2.25 m
∴
The distance s of how far the ball will go at the highest setting = 2.25m