Answer:
* in a tube with both ends open
λ = 2L / n n = 1, 2, 3,…
* tube with one end open and the other closed.
λ = 4L / n n = (2n ’+ 1 )
Explanation:
When a sound wave enters a pipe, a resonance process occurs, whereby only some wavelengths can occur.
* in a tube with both ends open
in this case there are maximums at each end, so if the length of the had is L
λ = 2L 1st harmonic
λ = 2 L / 2 2nd harmonic
λ = 2L / 3
λ = 2L / n n = 1, 2, 3,…
* In the case of a tube with one end open and the other closed.
At the open end there is a belly and at the closed end a node
λ = 4L 1st harmonic
λ = 4L / 3 3rd harmonic
λ = 4L / 5
λ = 4L / n n = 1, 3, 5,… odd
n = (2n ’+ 1 ) where n’ are all integers
Answer:
i can`t help without showing me the choses
Explanation:
Work done by force is given by formula
now here work done against friction is given so force of friction here is
It moved by three corridors with each measures
so total distance will be
now from above formula of work done we will say
so above is the work done to move three corridors
Answer:
55.128kg
Explanation:
P= m×v
or, m=P/v = 430/7.8 = 55.128 kg
