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2 years ago

Find the exact value of x

Mathematics

1 answer:

tresset_1 [31]2 years ago

6 0

ΔABC and ΔCBD are similar. Therefore we have the proportion:

$\dfrac{AB}{BC}=\dfrac{BC}{BD}\\\\AB=6;\ BC=x;\ BD=2$

Substitute:

$\dfrac{6}{x}=\dfrac{x}{2}$ <em>cross multiply</em>

$(x)(x)=(6)(2)\\\\x^2=12\to x=\sqrt{12}\\\\x=\sqrt{4\cdot3}\\\\x=\sqrt4\cdot\sqrt3\\\\\boxed{x=2\sqrt3}$

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What is the domain and range?

Rasek [7]

Answer:

Domain:- All real numbers

Range:-[3,infinite)

Step-by-step explanation:

In the function there's no value of x for which it is not defined thus domain is R.

Now a modulus will have always it's minimum value 0 thus minimum value of function is 0+3=3. And Max value of a modulus is infinite so infinite+3=infinite.

6 0

2 years ago

I need this Now (2x + 1)²

Alla [95]

Answer:

4x² + 4x + 1

Step-by-step explanation:

We know that (a + b)² = a² + 2ab + b², therefore, (2x + 1)² = 4x² + 4x + 1.

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3 years ago

Read 2 more answers

An election ballot asks voters to se4five city commissioners from a group of fifteen candidates. In how many wsys can this be do

svp [43]

That's "15 choose 5"

$\displaystyle{15 \choose 5} = \dfrac{15! }{5! 10!} = \dfrac{15 \cdot 14 \cdot 13 \cdot 12 \cdot 11}{5 \cdot 4 \cdot 3 \cdot 2 \cdot 1} = (15/(5(3))(14/2)(13)(12/4)(11)\\\\= 7(13)(3)(11)=231(13)=3003$

Answer: 3003 ways

8 0

2 years ago

All about simulitious equations

Korolek [52]

Answer:

On occasions you will come across two or more unknown quantities, and two or more equations

relating them. These are called simultaneous equations and when asked to solve them you

must find values of the unknowns which satisfy all the given equations at the same time.

Step-by-step explanation:

1. The solution of a pair of simultaneous equations

The solution of the pair of simultaneous equations

3x + 2y = 36, and 5x + 4y = 64

is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides

to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.

2. Solving a pair of simultaneous equations

There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a

single equation which involves the other unknown. The method is best illustrated by example.

Example

Solve the simultaneous equations 3x + 2y = 36 (1)

5x + 4y = 64 (2) .

Solution

Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation

6x + 4y = 72 (3)

Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:

6x + 4y = 72 − (3)

5x + 4y = 64 (2)

x + 0y = 8

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2 years ago

If a triangle has 23mm,20mm,13mm angles 62°,72°,46° what type of triangle is it

frutty [35]

I would draw the triangle then it would be easier to answer. It is not an equilateral because it is not equal on all sides. Perhaps scalene because all the sides are not the same.

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3 years ago