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Serggg [28]
3 years ago
8

Find the exact value of x

Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0

ΔABC and ΔCBD are similar. Therefore we have the proportion:

\dfrac{AB}{BC}=\dfrac{BC}{BD}\\\\AB=6;\ BC=x;\ BD=2

Substitute:

\dfrac{6}{x}=\dfrac{x}{2}    <em>cross multiply</em>

(x)(x)=(6)(2)\\\\x^2=12\to x=\sqrt{12}\\\\x=\sqrt{4\cdot3}\\\\x=\sqrt4\cdot\sqrt3\\\\\boxed{x=2\sqrt3}

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Answer:

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2 years ago
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Solve for x: one over eight (8x + 15) = 24
Vsevolod [243]
The answer is 177/8 or one hundred seventy seven over eigth.

1/8(8x + 15) = 24

Multiply both sides by 8:
8* 1/8(8x + 15) = 8 * 24
8x + 15 = 192


Subtract 15 from both sides:
8x +15 - 15 = 192 - 15
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Divide both sides by 8:
8x/8 = 177/8
x = 177/8

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3 years ago
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Sketch a graph of the polynomial function f(x) = –x3 + 5x2 – 2x – 8. Use the graph to complete the following:
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2 years ago
Which is the equation of the given line in slope-intercept form? (-1, 2) and (1, -4)
Natalka [10]
1. Find the slope using the slope formula.
\frac{2 - ( - 4)}{ - 1 - 1}  =  \frac{2 + 4}{ - 2}  =  -  \frac{6}{2}  =  -  \frac{3}{1}  =  - 3
2. Plug that slope and either point into an equation in slope-intercept form and solve for b.
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6 0
3 years ago
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Can someone help me with this
Brrunno [24]

Answer:

Step-by-step explanation:

8.) For a triangles sides to make sense, you must be able to add up two values of the triangle, and the result should be more than the third side. Add the lowest values and see if the result is greater than the biggest number:

4.2+7.9=12.1

12.1 is less than the given side, 13.3, so a triangle cannot have the lengths.

10.) 6<x<22

To find the range for the third side of the triangle, you need to find how small x can be (the missing side) and you need to see how large it can be.

You need to see how small it can be because any two sides have to be greater than the third side. You also need to see how big it can be because, if it's too big, the other two sides will be less than the third side, which would make an open shape (see picture).

To find the range, first see how small. Subtract the known sides:

22-6=16

So, x has to be greater than 16.

x > 16

Now add the known sides:

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x needs to be less than 28 for the other two sides to be greater than x:

x < 28

Insert the inequalities into a single inequality:

16 < x <28

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2 years ago
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