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Svetllana [295]
3 years ago
12

A student received the following grades last semester. Find the student's semester grade point average. An A is Algebra (3 credi

ts), a B in History ( 3 credits), A in sociology ( 3 credits) a D in English ( 3credits) and a C in seminar ( 2credits). An A is worth 4 points, a B is worth 3 points a C is worth 2 points and a D is worth 1 point.
Mathematics
1 answer:
kramer3 years ago
5 0

Answer:

If it is a simple average, the average is 2.8 points.

If it is a weigthed-by-credits average, the average is 2.86 points.

Step-by-step explanation:

To calculate the simple average of this 5 grades, we sum all the points and divide it by 5:

In Algebra: A = 4 points

In History: B = 3 points

In Sociology: A = 4 points

In English: D = 1 point

In Seminar: C = 2 points

Average = (4+3+4+1+2)/5 = 2.8 points

If the average is weighted by the credits, we must add each score multiplied by the credits and, in total, divide it by the total amount of credits.

weighted-average = \sum(points_i*credits_i)/\sum(credits_i)\\\\weighted-average = (4*3+3*3+4*3+1*3+2*2)/(3+3+3+3+2)\\weighted-average = 40 / 14 = 2.86

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Simplify the expression by using a double-angle formula. 2 sin 31°cos 31°
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The right hand side is exactly your expression, where x = 31^\circ

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6 0
3 years ago
Solve these simultaneous equations:
ivolga24 [154]

Answer:

1) We have the system:

5*x - 3*y = 15

4*x + 3*y = 6

To solve this, we first need to isolate one of the variables in one of the equations, let's isolate x in the first equation:

x = 15/5 + (3/5)*y = 3 + (3/5)*y

Now we can replace this in the other equation to get:

4*( 3 + (3/5)*y) + 3*y = 6

and solve this for y.

12 + (12/5)*y  + 3*y = 6

(12/5 + 3)*y = 6 - 12 = -6

(12/5 + 15/5)*y = -6

(27/5)*y = -6

y = -6*(5/27) = 1.11

Now we can replace this in the equation:

x = 3 + (3/5)*y

To get the value of x.

x = 3 + (3/5)*1.11 = 3.67

Then the solution of this system is the point (3.67, 1.11)

2) Now we have the system:

2*x + 5*y = 26

4*x + 3*y = 24

The solution method is the same as before:

x = 26/2 - (5/2)*y = 13 - (5/2)*y

Now we replace this in the other equation:

4*( 13 - (5/2)*y) + 3*y = 24

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52 - 7*y = 24

52 - 24 = 7*y

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now we replace this in the equatio:

x = 13 - (5/2)*y

x = 13 - (5/2)*4 = 13 - 10 = 3

The solution of this sytem is (3, 4)

3) Now we have the system:

3*x + 3*y = 39

2*x - 3*y = -2

first we isolate x in the first equation:

x = 39/3 - 3*y/3 = 13 - y

Now we can replace this in the other equation:

2*(13 - y) - 3*y = -2

26 - 2*y - 3*y = -2

26 - 5*y = -2

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4 0
3 years ago
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professor190 [17]

Answer:

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Step-by-step explanation:

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evablogger [386]
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The factors that are common to both numbers are 1 and 11 .

The greatest one is  <em>11</em> .


You asked for the "greatest", so you only get one of them.  If there were
more than one greatest, then you'd want to know which greatest was
greater than the other greatest.
6 0
3 years ago
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