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Ulleksa [173]
4 years ago
11

What is 5 to the power of 5? Brainliest

Mathematics
2 answers:
Strike441 [17]4 years ago
7 0
If you to know what it looks like in "number form " then its 5^5

Work to find out the answer
(5)(5)(5)(5)(5)

So, your answer would have be: 3, 125
kompoz [17]4 years ago
5 0
5x5x5x5x5? 5x5= 25, 25x5=125, 125x5= 625, and 625x5= 3125. So 3125 is your answer.
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What is the value of x
mezya [45]

Answer:

x=9.5

Step-by-step explanation:

In order to find the answer, we know that 6x + 4x - 5 = 90

Next we want to combine like terms: 10x - 5 = 90.

Now we have to add 5 to 90 in order to get x on its own.  10x = 95

Now solve for x by dividing 95 by 10: x=9.5

4 0
3 years ago
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Classify the triangle.<br>A. equilateral<br>B. scalene<br>C. isosceles
natima [27]

Answer:

It's a isosceles triangle........

I hope this is right....

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3 years ago
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1. Stop guys I need help! <br> 3 1/2 -2 1/2
ladessa [460]

Step-by-step explanation:

3 1/2 = 7 /2

2 1/2 = 5 /2

7/2 - 5/2

= 2/2 = 1

hope it helpful

6 0
3 years ago
A picture is 2” x 1.5”. Scale is 1:40cm. What are dimensions of original painting
Ann [662]
2*1.4=2.8
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New figure: 2.8 by 2.1
4 0
3 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
koban [17]

Answer:

a) No, because the probabilities of winning the 2nd game are dependant on the result of the 1st game. The probabilities are different if you win or lose the first game.

b) P=0.42

c) P=0.08

d)

X    |    P(X)

------------------

0    |    0.42

1     |    0.50

2    |    0.08

e) E(x)=0.66

s.d.=0.62

Step-by-step explanation:

a) No, because the probabilities of winning the 2nd game are dependant on the result of the 1st game. The probabilities are different if you win or lose the first game.

b) The probability of losing the first game is

P(G_1=L)=1-P(G_1=W)=1-0.4=0.6

The probability of losing the second game, given that the first game was lost is:

P(G_2=L|G_1=L)=1-P(G_2=W|G_1=L)=1-0.3=0.7

So the probability of losing both games is:

P(G_2=L\&G_1=L)=P(G_1=L)*P(G_2=L|G_1=L)=0.6*0.7=0.42

c) The probability of winning both games is:

P(G_2=W\&G_1=W)=P(G_1=W)*P(G_2=W|G_1=W)=0.4*0.2=0.08

d) The variable X can take values 0, 1 and 2.

X=0 is when both games are lost. This happens with probability P=0.42.

X=2 is when both games are won. This happens with probability P=0.08.

X=1 is when one game is won and the other is lost. This happens with probability P=1-0.42-0.08=0.50.

Then the table of probabilities become:

X    |    P(X)

------------------

0    |    0.42

1     |    0.50

2    |    0.08

e) The expected value is:

E(x)=\sum p_ix_i=0.42*0+0.50*1+0.08*2=0.00+0.50+0.16=0.66

The variance and standard deviation of x are:

V(x)=\sum p_i(x_i-E(x))^2\\\\V(x)=0.42(0-0.66)^2+0.50(1-0.66)^2+0.08(2-0.66)^2\\\\V(x)=0.42*0.4356+0.50*0.1156+0.08*1.7956\\\\V(x)=0.183+0.058+0.144=0.385\\\\\\\sigma=\sqrt{V(x)}=\sqrt{0.385}=0.62

The standard deviation can

5 0
3 years ago
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