Answer:
The larger integer is 
.
Step-by-step explanation:
Given: Two times the smaller of two consecutive integers is equal to 
more than the larger.
To find: The larger integer.
Solution:
Let the two consecutive integers be 
and 
, where the smaller integer is and larger integer is .
Now, according to question.
Two times the smaller integer 
more than the larger integer.
So, the smaller integer is 
, and the larger integer is 
Hence, the larger integer is 
Answer: look at the picture
Step-by-step explanation: Hope this help :D, Can I have a Brainliest I really needed it please
This area is equal to the sum of a circle with a radius of 5/2 in and a rectangle 5 by 15 in so:
A=πr^2+xy
A=π(2.5)^2+5*15
A=6.25π+75 in^2
A≈94.63 in^2 (to nearest hundredth) so
A≈95 in^2 (to nearest whole square inch)
/50 = /25•2
/25 • /2 further written as
5 • /2 simplified form
so A
Since you need an isolated variable to use the substitution method, we need to re-arrange one of the equations. This will probably be easiest to do with the first one.
Add 5y to both sides of the first equation.
x=10+5y
Now, in the second equation, put in 10+5y in any spot that has an x.
2(10+5y)-10y=20
Distribute the 2 to both numbers in the parenthesis.
20+10y-10y=20
Combine like terms.
20=20
This means that the two equations are actually the same. You can see this if you multiply the whole first equation by 2
2(x-5y=10)
2x-10y=20, which is the same as the second equation. Therefore, the two equations are actually the same one.
