What is acceleration?

A string with a mass density of 3 * 10^-3 kg/m is under a tension of 380 N and is fixed at both ends. One of its resonance frequ

Delvig [45]

Answer:

(a) the fundamental frequency of this string is 65 Hz

(b) the harmonics of the given frequencies are third and fourth respectively.

(c) the length of the string is 2.74 m

Explanation:

Given;

mass density of the string, μ = 3 x 10⁻³ kg/m

tension of the string, T = 380 N

resonating frequencies, 195 Hz and 260 N

For the given resonant frequencies;

$195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } ---(1)\\\\260 = \frac{n+1}{2l} \sqrt{\frac{T}{\mu} } ---(2)\\\\divide \ (2) \ by (1)\\\\\frac{260}{195} = \frac{n+1 }{n} \\\\260n = 195(n+1)\\\\260 n = 195 n + 195\\\\260n - 195n = 195\\\\65n = 195\\\\n = \frac{195}{65} \\\\n = 3$

(c) From any of the equations, solve for Length of the string (L);

$195 = \frac{n}{2l} \sqrt{\frac{T}{\mu} } \\\\195 = \frac{3}{2l}\sqrt{\frac{380}{3\times 10^{-3}} } \\\\l = \frac{3}{2\times 195}\sqrt{\frac{380}{3\times 10^{-3}} }\\\\l = 2.74 \ m$

(a) the fundamental frequency is calculated as;

$f_o = \frac{1}{2l} \sqrt{\frac{T}{\mu} } \\\\f_o = \frac{1}{2\times 2.74} \sqrt{\frac{380}{3\times 10^{-3} } }\\\\f_o = 65 \ Hz$

(b) harmonics of the given frequencies;

the first harmonic (n = 1) = f₀ = 65 Hz

the second harmonic (n = 2) = 2f₀ = 130 Hz

the third harmonic (n = 3) = 3f₀ = 195 Hz

the fourth harmonic (n = 4) = 4f₀ = 260 Hz

Thus, the harmonics of the given frequencies are third and fourth respectively.

7 0

3 years ago

Describe what would happen to the arrows if this magnet were picked up and dropped numerous times.

astraxan [27]

<h2>Arrows movment when magnet is Picked Up and Dropped many times.</h2>

If the magnet were picked up and dropped numerous times the arrows would point in a variety of directions. When the magnet is picked up then the arrow shows deflection in one point and when the magnet is dropped in the opposite direction. When it is picked up and dropped numerous times it will show deflection in many directions.

5 0

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natali 33 [55]

Work done=mgh
W=force*height
W=5N*0.50mts
W=2.5joule

6 0

4 years ago

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The centrifugal force which tends to throw the electrons out it's orbit as stated with mass moving velocity in an orbit of radiu

sammy [17]

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In Motion in Two and Three Dimensions, we examined the basic concepts of circular motion. An object undergoing circular motion, like one of the race cars shown at the beginning of this chapter, must be accelerating because it is changing the direction of its velocity. We proved that this centrally directed acceleration, called centripetal acceleration, is given by the formula

\[{a}_{\text{c}}=\frac{{v}^{2}}{r}\]

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3 years ago

An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only

kicyunya [14]

So i think that the question you are asking is the one of the exercise that says that the rope is very short and throws his bag also and you need to find the final speed of the bag tools. Well given the data we can use this next formulas to do this. First we are talking about conserve momentum: So we use a formula with the data like this:
<span>(135 + 13.0)kg * 1.50m/s = 135kg * V + 13.0kg * v </span>
<span>As we want V = 0; then </span>
<span>minimum v = 148kg * 1.50m/s / 13.0kg = 17.1 m/s
I hope is what you were looking for </span>

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3 years ago