Responder:
<h2>64 Julios
</h2>
Explicación:
La energía cinética se expresa mediante la fórmula KE = 1 / 2mv² donde;
m es la masa del cuerpo
v es la velocidad del objeto
Dado que el cuerpo se mueve horizontalmente con v = 4 m / sy después de un período de tiempo se mueve con v = 20 m / s, entonces la variación en la velocidad será de 20 m / s - 4 m / s = 16 m / s.
Parámetros dados
masa del objeto m = 0,5 kg
Variación de velocidad = 16 m / s
Variación de la energía cinética = 1/2 * 0,5 * 16²
Variación de la energía cinética = 1/2 * 0,5 * 256
Variación de la energía cinética = 0,5 * 128
<em>Variación de la energía cinética = 64 Julios</em>
Vx=cos60(4)
x-component of velocity
<span>If you think about it, it makes a right triangle when you combine all the different types of forces together such as v, vx and vy. Then, you can use trigonometry and soh cah toa in order to figure out vx. </span>
HEY THERE !!
It is called SUBLIMATION.
so the correct answer is (D).
Here is the answer. What is happening at the atomic level to give rise to the observed energy is that t<span>he </span>atomic level<span> is affected by the movement of electrons so as to </span><span>give rise to the observed energy. Hope this answers your question. Have a great day!</span>
Answer:
velocity = 1527.52 ft/s
Acceleration = 80.13 ft/s²
Explanation:
We are given;
Radius of rotation; r = 32,700 ft
Radial acceleration; a_r = r¨ = 85 ft/s²
Angular velocity; ω = θ˙˙ = 0.019 rad/s
Also, angle θ reaches 66°
So, velocity of the rocket for the given position will be;
v = rθ˙˙/cos θ
so, v = 32700 × 0.019/ cos 66
v = 1527.52 ft/s
Acceleration is given by the formula ;
a = a_r/sinθ
For the given position,
a_r = r¨ - r(θ˙˙)²
Thus,
a = (r¨ - r(θ˙˙)²)/sinθ
Plugging in the relevant values, we obtain;
a = (85 - 32700(0.019)²)/sin66
a = (85 - 11.8047)/0.9135
a = 80.13 ft/s²
