which of the following would not be taken into consideration when describing the quality of a sound? a. the number of the overto
2 answers:
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(a) 0.0021 s, 2926.5 rad/s
The frequency of the B note is
The time taken to make one complete cycle is equal to the period of the wave, which is the reciprocal of the frequency:
The angular frequency instead is given by
And substituting
f = 466 Hz
We find
(b) 20 Hz, 125.6 rad/s
In this case, the period of the sound wave is
T = 50.0 ms = 0.050 s
So the frequency is equal to the reciprocal of the period:
While the angular frequency is given by:
(c)
The minimum angular frequency of the light wave is
so the corresponding frequency is
and the period is the reciprocal of the frequency:
The maximum angular frequency of the light wave is
so the corresponding frequency is
and the period is the reciprocal of the frequency:
(d)
In this case, the frequency is
So the period in this case is
While the angular frequency is given by
Answer:
Please refer to the figure.
Explanation:
The magnitude of the magnetic field can be found by Biot-Savart Law. We should divide the loop into four components. Each component has a similar solution but their directions are quite different.
The directions can be found by right-hand rule. Point your index finger into the direction of current, point your middle finger towards the target point (0,0,a). Your thumb will show you the direction of magnetic field.
Answer:
The kinetic energy of the particle as it moves through point B is 7.9 J.
Explanation:
The kinetic energy of the particle is:
<u>Where</u>:
K: is the kinetic energy
: is the potential energy
q: is the particle's charge = 0.8 mC
ΔV: is the electric potential = 1.5 kV
Now, the kinetic energy of the particle as it moves through point B is:
Therefore, the kinetic energy of the particle as it moves through point B is 7.9 J.
I hope it helps you!