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3 years ago

What is the outcome of a star that runs out of hydrogen

Physics

1 answer:

givi [52]3 years ago

3 0

<h2>Answer: The nucleus becomes entirely helium.</h2>

To shine, the stars transform their hydrogen into helium by means of nuclear fusion. When at half of its life a star is without hydrogen, the nucleus becomes entirely helium and the star declines, becoming colder and brighter due to the energy generated by the nuclear reactions, then the star begins to contract.

Nevertheless, if the star is bigger, this helium will be also consumed and the nucleus transformed in Carbon, then in Oxigen, and so on. Being the last transformation Iron until the star delivers all its energy.

Note this process will depend on how massive the star is.

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Pls quickly brainliest to the first to anwser

fiasKO [112]

Answer:

8m/s^2

Explanation:

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2 years ago

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What do we measure sound intensity in?

stira [4]

Answer:

we measure sound intensity in Decibels.

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3 years ago

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A ball hits a wall. What is true about the magnitude of the force experienced by the ball compared with the force experienced by

Ivahew [28]

This is best understood with Newtons Third Law of Motion: for every action there is an equal and opposite reaction. That should allow you to see the answer.

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3 years ago

At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m². A fan is 30 m from the loudspeak

Klio2033 [76]

To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.

The expression for sound power is,

$P = AI$

Here,

A = Area

I = Intensity

P = Power

At the same time the area can be written as,

$A = \frac{\pi d^2}{4}$

Now the intensity is inversely proportional to the square of the distance from the source, then

$I \propto \frac{1}{r^2}$

The expression for the intensity at different distance is

$\frac{I_1}{I_2}= \frac{r^2_2}{r_1^2}$

Here,

$I_1$ = Intensity at distance 1

$I_2$ = Intensity at distance 2

$r_1$ = Distance 1 from light source

$r_2$ = Distance 2 from the light source

If we rearrange the expression to find the intensity at second position we have,

$I_2 = I_1 (\frac{r_1^2}{r_2^2})$

If we replace with our values at this equation we have,

$I_2 = (0.10W/m^2)(\frac{1.0m^2}{30.0m^2})$

$I_2 = 1.11*10^{-4} W/m^2$

Now using the equation to find the area we have that

$A = \frac{\pi (8.4*10^{-3}m)^2}{4}$

$A = 5.5*10^{-5}m^2$

Finally with the intensity and the area we can find the sound power, which is

$P = AI$

$P = (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)$

$P = 6.1*10^{-9}J/s$

Power is defined as the quantity of Energy per second, then

$E = 6.1*10^{-9}J$

8 0

3 years ago

Which statement is true about a pseudoscientific idea? A It is biased in its results. b It can be tested and observed. c It can

jeka94

Answer:

It can be replicated and verified.

Explanation:

Given that,

The following statements about a pseudoscientific idea.

(a). It is biased in its results.

(b). It can be tested and observed.

(c). It can be replicated and verified.

(d). It is improved with new information.

We know that,

Pseudo science :

In a pseudoscience, such as statements, trusts and facts about whom it is said these are scientific and logical but these statements is anomalous through the scientific method.

So, we can say that the statement is true about a pseudoscientific idea that is It can be replicated and verified

Hence, It can be replicated and verified.

(c) is correct option.

5 0

3 years ago