Answer:
a) τ = 0.672 N m
, b) θ = 150 rad
, c) W = 100.8 J
Explanation:
a) for this part let's start by finding angular acceleration, when the angular velocity stops it is zero (w = 0)
w = w₀ + α t
α = -w₀ / t
α = 120 / 2.5
α = 48 rad / s²
The moment of inertia of a cylinder is
I = ½ M R²
Let's calculate the torque
τ = I α
τ = ½ M R² α
τ = ½ 2.8 0.1² 48
τ = 0.672 N m
b) we look for the angle by kinematics
θ = w₀ t + ½ α t2
θ = ½ α t²
θ = ½ 48 2.5²
θ = 150 rad
c) work in angular movement
W = τ θ
W = 0.672 150
W = 100.8 J
The distance from a 27 mw point source of electromagnetic waves where the electric field amplitude 0. 060 v/m will be 21.21 m .
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.
The highest point of a wave is known as 'crest' , whereas the lowest point is known as 'trough'. Electromagnetic waves can be split into a range of frequencies. This is known as the electromagnetic spectrum.
c = 3 *
m/s
∈ = 8.85 *
/ N/ 
E = 0. 060 v/m
I = P / 4π
Also , I = c ∈
/2
= P / 4π I equation 1
substituting the value of I in equation 1
= 2 P / 4π (c ∈
)
= 2 * 27 *
/ 4 * 3.14 * 3 *
* 8.85 *
* 
r = 21.21 m
To learn more about Electromagnetic waves here
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The force applied to the second ball by the first ball is 6.734 × 10^-4 N.
<h3>What is impulse of force?</h3>
The impulse of force is defined as the sum of the average force and the duration it is applied.
If the mass of the item remains constant, the impulse of force equals the change in momentum of the object.
Given that: mass of a metal sphere: m = 0.026 kg.
Initial speed of the sphere: u = 3.7 m/s.
When the sphere stops completely, its change in momentum = mu - 0
= 0.026×3.7 N-s.
= 0.0962 N-s.
As the spheres are in contact for 0.007s before the second sphere is shot off down the track, the force applied to the second ball =
change in momentum of 1st ball × time of contact
= 0.0962 × 0.007 N
= 0.0006734 N
= 6.734 × 10^-4 N.
Hence, the force applied to the second ball is 6.734 × 10^-4 N.
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Answer:
The time that will pass between the feeling and hearing the explosion is 2,86 secs
Explanation:
First, let's calculate the time that the wave takes to travel until the actors feel the explosion:

Now, the time that pass while the actors hear the sound is:
<em>(Remember that the sound speed in the air is 340 m/s on average)</em>

So, the time between the feeling and hearing is 3,23 - 0,37 = 2,86 secs