Question

Estimate the average power of a water wave when it hits the chest of an adult standing in the water at the seashore. Assume that the amplitude of the wave is 0.56 m , the wavelength is 2.0 m , and the period is 3.4 s . Assume that the area of the chest is 0.14 m^2.

Answer 1

Answer:

$P=45.2W$

Explanation:

From the question we are told that:

Amplitude $A=0.56m$

Period $T=3.4s$

Wavelength $\lambda=2.0$

Area $a=0.14m^2$

Generally the equation for Power is mathematically given by

$Power = 2 \pi ^2 \rho a(\frac{\lambda}{T})(\frac{1}{T})*A$

$P= 2 3.142^2 1025 0.14(\frac{2.0}{3.4})(\frac{1}{3.4})^2*0.56^2$

$P=45.2W$