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Dafna1 [17]
2 years ago
12

Estimate the average power of a water wave when it hits the chest of an adult standing in the water at the seashore. Assume that

the amplitude of the wave is 0.56 m , the wavelength is 2.0 m , and the period is 3.4 s . Assume that the area of the chest is 0.14 m^2.
Physics
1 answer:
Nana76 [90]2 years ago
8 0

Answer:

P=45.2W

Explanation:

From the question we are told that:

Amplitude A=0.56m

Period T=3.4s

Wavelength \lambda=2.0

Area a=0.14m^2

Generally the equation for Power is mathematically given by

Power = 2 \pi ^2 \rho a(\frac{\lambda}{T})(\frac{1}{T})*A

P= 2 3.142^2 1025 0.14(\frac{2.0}{3.4})(\frac{1}{3.4})^2*0.56^2

P=45.2W

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