Answer:
519.62 m/s
Explanation:
Applying,
v = √(T/m').............. Equation 1
Where v = velocity of the wave, T = Tension on the string, m' = mass per unit length of the string
From the question,
Given: T = 1350 N, m' = 0.005 kg/m
Substitute these values into equation 1
v = √(1350/0.005)
v = √(270000)
v = 519.62 m/s
Answer:
Final velocity, v = 25.3 m/s
Explanation:
Initial velocity of a locomotive, u = 19 m/s
Acceleration of the locomotive, a = 0.8 m/s²
Length of station, d = 175 m
We need to find its final velocity (v) when the nose leaves the station. It can be calculated using the third law of motion :
v = 25.31 m/s
v = 25.3 m/s
When the nose leaves the station, it will move with a velocity of 25.3 m/s. Hence, this is the required solution.
Answer:
The answer is 2 because the formula is
wavelength=speed/frequency