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Degger [83]
4 years ago
12

The blade on a typical table saw rotates at 3300 revolutions per minute. calculate the linear velocity in miles per hour of one

of the teeth at the edge of the 14 inch diameter blade.
Physics
2 answers:
yKpoI14uk [10]4 years ago
5 0
C=d(pi)=43.98in. Tip travels 3300 x C = 145,134in per min. (145,134in/min)(1ft/12in)(1 mile/5280ft)(60min/1 hr) = 137.4mph. 
marshall27 [118]4 years ago
3 0

Answer:

Linear speed of the blade is 136.81 mph

Explanation:

It is given that,

Angular speed of the blade of table saw, \omega=3300\ rev/min=345.57\ rad/s

Diameter of the blade, d = 14 inch = 0.3556 m

Radius of the blade, r = 0.177 m

We need to find the linear velocity of the blade. The relation between linear velocity and the angular speed is :

v=r\times \omega

v=0.177\times 345.57

v = 61.16 m/s

Since, 1 m/s = 2.23 mph

So, v = 136.81 mph

Therefore, the linear velocity of the blade is 136.81 mph.

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A group of physics students hypothesize that for an experiment they are performing, the speed of an object sliding down an incli
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v = 2.974

Explanation:

Perhaps the formula should be

v = √(2*g*d (sin(θ) - uk*cos(θ) )                    This is a bit easier to read.

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6 0
4 years ago
Read 2 more answers
A body of mass 400 kg is suspended at a lower end of a light vertical chain and is being pulled up vertically. Initially the bod
yKpoI14uk [10]

Answer:31.62 m/s

Explanation:

Given

mass of body m=400 kg

Pull on chain is F_1=6000g N=60 kN

Pull get smaller at the rate of F_2=360g N/m

Net Upward Force F=6000 g-360 g\times 10=24 kN

net acceleration a=\frac{F}{m}

a=\frac{24\times 1000}{m}

a=\frac{24000}{400}

a=60 m/s^2

but g is acting downward

a_{net}=a-g=60-10=50 m/s^2

using v^2-u^2=2 as

here initial velocity is zero

v^2=2\times 50\times 10

v=31.62 m/s

7 0
4 years ago
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