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sergey [27]
3 years ago
11

you are trying to figure out the voltage of a battery when you know the current and the resistance. the current(i) is 25 Amps, a

nd the resistance (R) is 10 ohms. Use the right form of I=VIR
Physics
2 answers:
Brums [2.3K]3 years ago
8 0

Answer:

V= 250 volts

Explanation:

V=IR

V=25*10

V=250 volts

dalvyx [7]3 years ago
6 0

Answer: 250 V

Explanation: Ohm's Law is expressed in the given equation:

V = I x R

Substitute the values of I ( current) and R ( resistance)

V = 25 A x 10 ohms

= 250 V

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Answer:

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Explanation:

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A student wants to create a 6.0V DC battery from a 1.5V DC battery. Can this be done using a transformer alone
shusha [124]

Answer:

Therefore, we need an invert, and a rectifier, along with the transformer to do the job.

Explanation:

A transformer, alone, can not be used to convert a DC voltage to another DC voltage. If we apply a DC voltage to the primary coil of the transformer, it will act as short circuit due to low resistance. It will cause overflow of current through winding, resulting in overheating pf the transformer.

Hence, the transformer only take AC voltage as an input, and converts it to another AC voltage. So, the output voltage of a transformer is also AC voltage.

So, in order to convert a 6 V DC to 1.5 V DC we need an inverter to convert 6 V DC to AC, then a step down transformer to convert it to 1.5 V AC, and finally a rectifier to convert 1.5 V AC to 1.5 V DC.

<u>Therefore, we need an invert, and a rectifier, along with the transformer to do the job.</u>

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3 years ago
A terain tarvels 120 I in 2 hours and 30 mins .what is its average speed
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It's speed is 48 km/hr.

Explanation:

6 0
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Read 2 more answers
What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a perio
pantera1 [17]
If the period of a satellite is T=24 h = 86400 s that means it is in geostationary orbit around Earth. That means that the force of gravity Fg and the centripetal force Fcp are equal:

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where m is mass, v is the velocity of the satelite and R is the height of the satellite and g=G*(M/r²), where G=6.67*10^-11 m³ kg⁻¹ s⁻², M is the mass of the Earth and r is the distance from the satellite. 

Masses cancel out and we have:

G*(M/r²)=v²/R, R=r so:

G*(M/r)=v²

r=G*(M/v²), since v=ωr it means v²=ω²r² and we plug it in,

r=G*(M/ω²r²),

r³=G*(M/ω²), ω=2π/T, it means ω²=4π²/T² and we plug that in:

r³=G*(M/(4π²/T²)), and finally we take the third root to get r:

r=∛{(G*M*T²)/(4π²)}=4.226*10^7 m= 42 260 km which is the height of a geostationary satellite. 
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3 years ago
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