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klasskru [66]
3 years ago
11

A 0.700-kg ball is on the end of a rope that is 2.30 m in length. The ball and rope are attached to a pole and the entire appara

tus, including the pole, rotates about the pole’s symmetry axis. The rope makes a constant angle of 70.0° with respect to the vertical. What is the tangential speed of the ball?
Physics
1 answer:
otez555 [7]3 years ago
7 0

Answer:

The tangential speed of the ball is 11.213 m/s

Explanation:

The radius is equal:

r=2.3*sin70=2.161m (ball rotates in a circle)

If the system is in equilibrium, the tension is:

Tcos70=mg\\Tsin70=\frac{mv^{2} }{r}

Replacing:

\frac{mg}{cos70} sin70=\frac{mv^{2} }{r} \\Clearing-v:\\v=\sqrt{rgtan70}

Replacing:

v=\sqrt{2.161x^{2}*9.8*tan70 } =11.213m/s

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Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

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Given that

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Lets find strain:

Case 1 :

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ε = 0.005

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ε '=0.0021

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

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