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3 years ago

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A 0.700-kg ball is on the end of a rope that is 2.30 m in length. The ball and rope are attached to a pole and the entire appara

tus, including the pole, rotates about the pole’s symmetry axis. The rope makes a constant angle of 70.0° with respect to the vertical. What is the tangential speed of the ball?

1 answer:

otez555 [7]3 years ago

7 0

Answer:

The tangential speed of the ball is 11.213 m/s

Explanation:

The radius is equal:

$r=2.3*sin70=2.161m$ (ball rotates in a circle)

If the system is in equilibrium, the tension is:

$Tcos70=mg\\Tsin70=\frac{mv^{2} }{r}$

Replacing:

$\frac{mg}{cos70} sin70=\frac{mv^{2} }{r} \\Clearing-v:\\v=\sqrt{rgtan70}$

Replacing:

$v=\sqrt{2.161x^{2}*9.8*tan70 } =11.213m/s$

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Answer:

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Explanation:

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3 years ago

How fast would 40 Newtons of force accelerate a 2 kg object?

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Answer:

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Explanation:

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Which model best represents a pattern?

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3 years ago

Read 2 more answers

An 80-kg astronaut becomes separated from his spaceship. He is 15.0 m away from it and at rest relative to it. In an effort to g

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The astronaut will take 300 seconds

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, the total momentum of the astronaut+object system must be conserved.

Initially, they are both at rest, so their total momentum is zero:

$p=0$

After the astronaut throws the object, their total momentum is:

$p=MV+mv$

where:

M = 80 kg is the mass of the astronaut

V is the final velocity of the astronaut

m = 500 g = 0.5 kg is the mass of the object

v = 8.0 m/s is the velocity of the object

Since momentum is conserved, we can write

$0=MV+mv$

And solving for V,

$V=-\frac{mv}{M}=-\frac{(0.5)(8.0)}{80}=-0.05 m/s$

Which means that he starts moving at 0.05 m/s in the direction opposite to the object.

Now the astronaut needs to cover a distance of

d = 15.0 m

And his speed is

v = 0.05 m/s

Therefore, the time taken is

$t=\frac{d}{v}=\frac{15.0}{0.05}=300 s$

Learn more about momentum here:

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3 years ago

A closed-end organ pipe is used to produce a mixture of sounds. The third and fifth harmonics in the mixture have frequencies of

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Answer:

$F_1=366.67Hz$

Explanation:

From the question we are told that:

Frequency of 3rd harmonics $F_3=1100$

Frequency of 5th harmonics $F_3=1833$

Generally the equation for Wavelength at 3rd Harmonics is mathematically given by

$\lambda_3=\frac{4}{3}l$

Therefore

$F_3=\frac{3v}{4l}$

Generally the equation for Wavelength at 1st Harmonics is mathematically given by

$\lambda_1=\frac{4}{1}l$

Therefore

$F_1=\frac{v}{4l}$

Generally the equation for the frequency of the first harmonic is mathematically given by

$F_1=\frac{F_3}{3}$

$F_1=\frac{1100}{3}$

$F_1=366.67Hz$

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3 years ago