Given a volume of 1000. cm^3 of an ideal gas at 300. K, what volume would it occupy at a temperature of 600. K?
1 answer:
Answer:2000cm3
Explanation: this is Charles' law which has the expression V1/T1 = V2/T2
Making V2 the subject of the formula, we have that
V2 = V1 x T2/ T1
= 1000 x 600 / 300
= 2000cm3
Where:
V1= initial velocity
V2= Final velocity
T1= initial temperature
T2= Final temperature
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