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erastovalidia [21]
3 years ago
5

The molecular formula of butane is C4H10. It is obtained from petroleum and is used commonly in LPG (Liquefied Petroleum Gas) cy

linders (a common source of cooking gas). It has two arrangements of carbon atoms: a straight chain and a branched chain. Using this information, draw the structure of the tertiary butyl radical that will form upon removal of a hydrogen atom.

Chemistry
2 answers:
LUCKY_DIMON [66]3 years ago
8 0

Answer:

Explanation:

Butane is an alkane and has no multiple bond in it.

The isomers of butane are

a) n-butane

b) t-butane

The structures are shown in the figure.

The most stable radical will be tertiary butyl radical.

The structures are shown in figure.

qaws [65]3 years ago
5 0

Answer:

On the attached document.

Explanation:

Hello,

At first, if we're looking for the tertiary arrangement we must consider butane's branched structure which is shown on the attached document whose name is tert-butane. Afterwards, one must remove one hydrogen to let the tert-butyl radical, which is stood for a dot above the tertiary carbon, to be formed.

Best regards.

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Answer:

ρ=m÷v

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A typical person has an average heart rate of 75.0 beats/min. Calculate the following a)How many beats does she have in 7.0 year
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Let us first convert years to minute.

7 years * (365 days / year) * (24 hours / day) * (60 minutes / hour) = 3,679,200 minutes

 

a. beats = 75.0 beats/min * 3,679,200 minutes

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Since the original given is 7.0 years (2 significant figures), therefore:

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b beats = 75.0 beats/min * 3,679,200 minutes

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<span>beats = 275,900,000 beats</span>

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7 0
2 years ago
The water in a pressure cooker boils at a temperature greater than 100°C because it is under pressure. At this higher temperatur
vazorg [7]

Answer:

the activation energy Ea = 179.176 kJ/mol

it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

Explanation:

From the given information

T_1 = 100^0 C = 100+273 = 373 \ K \\ \\  T_2 = 113^0 C = 113 + 273 = 386 \ K

R_1 = \dfrac{1}{7}

R_2 = \dfrac{1}{49}

Thus; \dfrac{R_2}{R_1} = 7

Because at 113.0°C; the rate is 7 time higher than at 100°C

Hence:

In (7) = \dfrac{Ea}{8.314}( \dfrac{1}{373}- \dfrac{1}{386})

1.9459 = \dfrac{Ea}{8.314}* 9.0292  *10^{-5}

1.9459*8.314 = Ea * 9.0292*10^{-5}

16.1782126= Ea * 9.0292*10^{-5}

Ea = \dfrac{16.1782126}{ 9.0292*10^{-5}}

Ea = 179.176 kJ/mol

Thus; the activation energy Ea = 179.176 kJ/mol

b)

here;

T_2 = 386 \  K  \\ \\T_1 = (89.8 + 273)K = 362.8 \ K

In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})

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In (\dfrac{R_2}{R_1}) = 0.00357

\dfrac{R_2}{R_1}= e^{0.00357}

\dfrac{R_2}{R_1}= 1.0035

where ;

R_2 = \dfrac{1}7{}

R_1 = \dfrac{1}{t}

Now;

\dfrac{t}{7}= 1.0035

t = 7.0245 mins

Therefore; it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

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