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KATRIN_1 [288]
2 years ago
12

Why methylated spirits burn?​

Chemistry
1 answer:
pishuonlain [190]2 years ago
5 0

Answer:

Methylated \:  spirits \:  are \:   \: extremely \:  flammable.

Explanation:

Incorrect use has resulted in accidents and disfiguring burns. Never leave a methylated spirit appliance unattended. Also make sure that the camping stove or appliance is on a flat surface and that the fuel cannot spill out.

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How many atoms are in 13.97 liters of water vapor at STP
Arisa [49]
<span>Let's </span>assume that water vapor has ideal gas behavior. <span>
Then we can use ideal gas formula,
PV = nRT<span>

</span><span>Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span></span>⁻¹ K⁻¹) and T is temperature in Kelvin.<span>
<span>
</span>P = 1 atm = 101325 Pa (standard pressure)
V = 13.97 L = 13.97 x 10</span>⁻³ m³<span>
n = ?
R = 8.314 J mol</span>⁻¹ K⁻¹<span>
T = 0 °C = 273 K (standard temperature)
<span>
By substitution,
</span>101325 Pa x 13.97x 10</span>⁻³ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 273 K<span>
                                          n = 0.624 mol
<span>
Hence, the moles of water vapor at STP is 0.624 mol.

According to the </span></span>Avogadro's constant, 1 mole of substance has 6.022 × 10²³ particles.
<span>
Hence, number of atoms in water vapor = 0.624 mol x </span>6.022 × 10²³ mol⁻¹
<span>                                                                = 3.758 x 10</span>²³<span>

</span>
5 0
3 years ago
A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain
sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

-w=\frac{dm}{dt}

w is the mass flow

m is the mass of salt

-v*C=\frac{dm}{dt}

v is the volume flow

C is the concentration

C=\frac{m}{V+(6-3)*L/min*t}

-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}

-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}

-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)

-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)

m=90kg*[2000L/(2000L+3*L/min*t)]

a) Initially: t=0

m=90kg*[2000L/(2000L+3*L/min*0)]=90kg

b) t=210 min (3.5 hr)

m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg

c) If time trends to infinity the  division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0
3 years ago
The mass of an electron is approximately equal to 1 over 1,836 of the mass of 1. a positron 2. a proton 3. an atom of helium 4.
lianna [129]
Hello!

It would be A, the proton.
5 0
3 years ago
Read 2 more answers
Which of the following is a physical property of water?
Kamila [148]
Water is NOT flammable.
6 0
3 years ago
how many electrons does it take to fill the mos formed from the combination of the 3s orbitals of two atoms?
Musya8 [376]

The number of electrons it take to fill the mos formed from the combination of the 3s orbitals of two atoms simply is 14 electrons.

<h3>How electrons are distributed in the 3s orbitals.</h3>

The 3s orbital possess two different spherical nodes which is highly connected with the principal quantum number. In order words, it has 2 radial nodes. Also the shape of the 3s orbital is spherical in shape.

That being said, from the context of the above given task, the number of electrons which fill the mos formed from the combination of the 3s orbitals of two atoms is fourteen electrons.

However, the electron configuration of an atom simply is the arrangement of electrons in the electron shell or orbit of the atom of that element.

In conclusion, it can be deduced from above s orbital has a maximum of two electrons and this energy increases as the orbitals increases.

Read more on electron:

brainly.com/question/860094

#SPJ1

7 0
1 year ago
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