Hey there!:
The Ksp of PbBr2 is 6.60*10⁻⁶
PbBr2 <=> Pb2+ + 2 Br-
Ksp = [Pb2+][Br-]2 = 6.60 x 10⁻⁶
Therefore:
In 0.500 M KBr solution:
[Br-] = [KBr] = 0.500 M assuming [Br-]PbBr2 << [Br-]KBr
Ksp = [Pb2+] * (0.500)² = 6.60 x 10⁻⁶
Molar solubility = [Pb²⁺] = 2.64 x 10⁻⁵ M
(Check [Br-]PbBr2 = 2 * ( 2.64 x 10⁻⁵M ) << 0.500 M so assumption is valid)
Answer : [Pb²⁺] = 2.64 x 10⁻⁵ M
Hope that helps!
C. MgCl2
This structure forms a ionic bond, which are generally stronger than covalent bonds. All of the other choices are covalent.
yess the dog will walk
Answer:
92.1 g
Explanation: